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Anarel [89]
4 years ago
10

Several weeks ago an article appeared in the press comparing the Fit Bit exercise monitor to the Garmin monitor. In fact, earlie

r reports suggested that the Fit Bit monitor was inaccurate in a number of its readings.You are a statistician who has been asked to compare the Fit Bit tracker to the Garmin tracker to see if there are significant differences between them. The variable you are interested in studying is the number of steps an individual takes during the day when wearing one of these trackers. You are being asked to construct a study for this question. Please write out your answers to the following questions. You have not undertaken the survey as of yet, so all you have to provide is a plan.How large a sample would you consider taking for each tracker? In other words you have to decide n1 and n2.What would your null and alternative hypotheses be?Are you conducting a dependent or independent test?What reading would you record for each member of your sample?Would you have any restriction on the individuals included in your sample? Would you restrict them by age, weight, athleticism? Why?Do you think you would know the standard deviations for each population (tracker)? What should be done about this?Now suppose the question changes and you are asked by a medical society to measure the effectiveness of the Fit Bit tracker. Your question would be does use of the Fit Bit tracker lead its users to lose weight?What test would you suggest conducting here? Would you use two independent samples or a dependent sample? Why?What data would you collect?What would your null and alternative hypotheses be?
Mathematics
1 answer:
MAXImum [283]4 years ago
6 0

Answer:

thank you for replying

Step-by-step explanation:

thank you for replying

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Answer:

you taking that end of module assessment too?

Step-by-step explanation:

5 0
3 years ago
In the game "Telephone," one person receives a message and then passes it on to one or more other people. The number of people w
lisov135 [29]
B. version 2 hope this helps

7 0
3 years ago
The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax
charle [14.2K]
First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx

Let u=e^x, so that \mathrm dx=\dfrac{\mathrm du}u, and the integral is equivalent to

\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du

The integrand is continuous everywhere except u=0, but that's okay because we have \lim\limits_{u\to0^+}\frac{\sin u}u=1. This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx

By the same substitution as before, we can write this as

\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du

The half-angle identity for sine allows us to rewrite as

\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du

and replacing v=2u, \dfrac{\mathrm dv}2=\mathrm du, we have

\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))

where \gamma is the Euler-Mascheroni constant and \mbox{Ci} denotes the cosine integral function.
5 0
4 years ago
Solve the equation below. Graph the solution on a number line.<br><br> w/2 = -1<br><br> w =
8_murik_8 [283]
Multiply both sides by 2

w= -1×2

simplify 1×2 to 2

w= -2
5 0
3 years ago
-1/2 divided by 1 3/4 as a fraction in simplest form
Helen [10]

\Large\textsf{\textbf{Answer\;:}}}

\large\textsf{refer\:to\:the\:"calculations"\:section\:of\:this\:ans}

\Large\textsf{\textbf{Calculations\::}}

-\displaystyle\frac{1}{2} :1\frac{3}{4}

First , convert the mixed number (the fraction we are dividing by in the given maths problem) into an improper fraction .

Multiply the whole part (1) times the denominator (4) and add the numerator . The result is the numerator of our fraction , and the denominator stays the same .

So now our maths problem looks as follows :

-\displaystyle\frac{1}{2} :\frac{7}{4}

Now turn the fraction you are dividing by over :

-\displaystyle\frac{1}{2} *\frac{4}{7}

Now multiply the numerator of the first fraction times the numerator of the second fraction :

4

Perform the same operation with the denominators :

-4/14

So the result is :

-\displaystyle\frac{4}{14}

Since the above fraction is not in it's simplest form , we divide the top and bottom by 2 (a common factor of both 4 and 14) :

-\displaystyle\frac{2}{7}

\footnotesize\textsf{hope\:helpful~}

8 0
3 years ago
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