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spayn [35]
3 years ago
7

What is the range of the function g(x) = 3x^2 - 6x + 3 when the domain is defined as the set of integers, x, such that 0<=x&l

t;=4? Show all work.
Mathematics
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

Range is  3 <= g(x) <= 27.

Step-by-step explanation:

The range  is the values of g(x) for the given domain.

When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.

When x = 4 g(x) = 3(4)^2 - 6(4) + 3 =  27.

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