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3 years ago

I need help with this

Mathematics

1 answer:

Akimi4 [234]3 years ago

5 0

Answer:

-9 < 26

Explanation of the Inequality:

This inequality means that the low temperature in Anchorage, Alaska was lower than the low temperature in Flagstaff, Arizona.

***Draxx them sklounst***

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Write a statement

nekit [7.7K]

9514 1404 393

Answer:

C) ΔDCE ≅ ΔDQR

Step-by-step explanation:

Corresponding vertices can be identified by the number of arcs signifying congruence.

1 mark: angles D and D

2 marks: angles C and Q

3 marks: angles E and R

Corresponding angles are listed in the same order in the congruence statement:

ΔDCE ≅ ΔDQR

6 0

2 years ago

Now Ann is x years old and her sister is eight years younger than her. After five years , Anne's age is twice the age of her sis

svp [43]

Answer:

You can refer to the given attachment

7 0

1 year ago

Solve. x² – 8x - 12 = 36

professor190 [17]

sorry answered the wrong one..

7 0

3 years ago

WILL BRAINLIEST IF ANSWER IS RIGHT!!!!!!!!!!!!!!!!!!!!!! PLEASE HELP!!!!!! 50-100 POINTS!!!!!!!!

zzz [600]

Answer:

241 tons

Step-by-step explanation:

312-170=142

142÷2=71

170+71=241

241+71=312

train B weighs 241 tons

3 0

3 years ago

Read 2 more answers

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago