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kirza4 [7]
3 years ago
11

Kelsie sold digital cameras on her website . She bought the cameras for $65 each and includes a 60% markup to get the selling pr

ice . To the nearest dollar , what was the selling price for one camera ?
Mathematics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

$104

Step-by-step explanation:

First, convert 60% to a decimal.

60% = 0.6

Now, multiply the cost to buy the camera ($65) by the decimal.

$65 × 0.6 = $39

Now, add this amount to the amount it cost to buy the camera.

$65 + $39 = $104

The selling price for the camera will be $104.

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Cate and Elena were playing a card game. The stack of cards in the middle had 24 cards in it to begin with. Cate added 5 cards t
sammy [17]

Answer:

23

Step-by-step explanation:

because i said so oki

6 0
3 years ago
12 1/2 - (-4 1/2) =​
puteri [66]

Answer: the answer here is 8

Step-by-step explanation:

just lay it out up to down, divide annnnnd SHABLAM you got the answer :)

3 0
3 years ago
Let Y1 and Y2 be independent exponentially distributed random variables, each with mean 7. Find P(Y1 > Y2 | Y1 < 2Y2). (En
ArbitrLikvidat [17]

<em>Y</em>₁ and <em>Y</em>₂ are independent, so their joint density is

f_{Y_1,Y_2}(y_1,y_2)=f_{Y_1}(y_1)f_{Y_2}(y_2)=\begin{cases}\frac1{49}e^{-\frac{y_1+y_2}7}&\text{for }y_1\ge0,y_2\ge0\\0&\text{otherwise}\end{cases}

By definition of conditional probability,

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = P((<em>Y</em>₁ > <em>Y</em>₂) and (<em>Y</em>₁ < 2 <em>Y</em>₂)) / P(<em>Y</em>₁ < 2 <em>Y</em>₂)

Use the joint density to compute the component probabilities:

• numerator:

P((Y_1>Y_2)\text{ and }(Y_1

=\displaystyle\frac1{49}\int_0^\infty\int_{\frac{y_1}2}^{y_1}e^{-\frac{y_1+y_2}7}\,\mathrm dy_2\,\mathrm dy_1

=\displaystyle-\frac17\int_0^\infty\int_{-\frac{3y_1}{14}}^{-\frac{2y_1}7}e^u\,\mathrm du\,\mathrm dy_1

=\displaystyle-\frac17\int_0^\infty\left(e^{-\frac{2y_1}7} - e^{-\frac{3y_1}{14}}\right)\,\mathrm dy_1

=\displaystyle-\frac17\left(-\frac72e^{-\frac{2y_1}7} + \frac{14}3 e^{-\frac{3y_1}{14}}\right)\bigg|_0^\infty

=\displaystyle-\frac17\left(\frac72 - \frac{14}3\right)=\frac16

• denominator:

P(Y_1

(I leave the details of the second integral to you)

Then you should end up with

P(<em>Y</em>₁ > <em>Y</em>₂ | <em>Y</em>₁ < 2 <em>Y</em>₂) = (1/6) / (2/3) = 1/4

5 0
3 years ago
Determine whether the ordered pair (1, 1) is a solution of the inequality. y ≤ -3x+1
solong [7]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{(1, 1) is NOT a solution of the inequality}

-------------------------------------------------------------------------------------------------------------

Given:  y \le-3x + 1

Find:  \textsf{Determine if (1, 1) is a solution of the inequality}

Solution:  In order to determine if (1, 1) is a solution we need to plug in 1 for the x values and 1 for the y values and see if the equation evaluated to true.

<u>Plug in the values</u>

  • y \le-3x + 1
  • 1 \le-3(1) + 1

<u>Simplify</u>

  • 1 \le-3 + 1
  • 1 \le-2

As we can see the expression states that 1 is less than or equal to -2 which is false therefore (1, 1) is NOT a solution of the inequality.

3 0
2 years ago
Finding a parametric description of the solution set of a linear system is the same as solving the system.Choose the correct ans
Grace [21]

Answer:

The answer is "Choice B".

Step-by-step explanation:

Please find the complete question in the attached file.

In this question, in all choices, the choice (B) is Correct because in the declaration of the statement Only when the process has had at least another answer could a candidate solution for more than just a linear model explicitly uses a parametric description that's why the given statement is true.

7 0
3 years ago
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