Furthest to the left is a Hexagon. Middle is an Octagon. Furthest to the right is a Decagon.
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
Answer:
3x-526
Step-by-step explanation:
the 3x would go in the beginning. then you subtract (-4-522)= -526.
No nickles = 2x and that of dimes = 7x so 2x = 350 get x and the no of dimes
so like 2x = 350 divide by 2 on both sides so x = 175 ... and no of dimes = 7*x = 7*175 = 1225
Hope it helps :)
<span>When 20 is increased by 30% of itself
</span><span>When 20 is added to by (30% OF 20)
</span><span>
20 + (30% x 20)
</span><span>20 + (0.3 x 20)
</span><span>
20 + (6)
</span>26
