2x+3=10^3 now solve for x.....hope it helps
Answer:
1) DC and DG
2) D
3) <GDE
4) acute
5) obtuse
Step-by-step explanation:
1) DC and DG
2) D
3) <GDE
4) acute
5) obtuse
Answer:
hilghkiii
Step-by-step explanation:
Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.





Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
<h2>

</h2>

。。。。。。。。。。。。。。。。。。。。。。。。。。。。
- 》5! ( 2 × 1 ) - 4! × 3!
- 》5! ( 2 ) - ( 4! × 3! )
- 》5! ( 2 ) - ( ( 4 × 3 × 2 × 1 ) × ( 3 × 2 × 1 ) )
- 》5! ( 2 ) - ( 24 × 6 )
- 》5! ( 2 ) - 144
- 》( 5 × 4 × 3 × 2 × 1 ) ( 2 ) - 144
- 》120 ( 2 ) - 144
- 》240 - 144
- 》90
。。。。。。。。。。。。。。。。。。。。。。。。。。。。
