The equation r = square root of theta can be translated into a semi-circle through the simplification to r^2 = theta. When theta is 0, r is zero. When r is -3pi/2, r2 is equal to 9/4 pi^2. The area of the semi-circle is equal to pi r^2 /2. Hence the area is equal to 34.88 units^2

6 0

3 years ago

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PLLLZZZZ HELPPP MEE

Amanda [17]

Answer:

construct PQ
construct circles of radius PQ centered at P and Q
label one of the points of intersection R
Construct PR and QR

Step-by-step explanation:

You should actually do this some time. It will help you understand the construction process and help you remember the steps. It may even help you figure out why it works.

3 0

3 years ago

Evaluate the sum or explain why it diverges: Sigma^infinity_k = 3(-3/2)^k

LenaWriter [7]

Answer:

Step-by-step explanation:

Remember that in the geometric serie if | r | < 1 the serie converges and if | r | ≥1 the serie diverges.

I suppose that the serie starts at 0, so using the geometric serie with r = | $\frac{-3}{2}$ | > 1 the serie diverges.