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son4ous [18]
4 years ago
7

ABC and AED are straight lines. BE and CD are parallel. AC = 12.3cm AB = 8.2cm BE = 3.8cm a) Work out length CD. AD = 9.15cm

Mathematics
1 answer:
elena-14-01-66 [18.8K]4 years ago
6 0

Answer:

15.33cm

Step-by-step explanation:

when you try to draw out this figure, satisfying the fact that Ad and Ac are both straight lines. you find the ultimately  it forms a right-angled triangle with sides AC and AD and hypotenuse CD.

Now, you may use Pythagoras theorem to solve:

AC^2 + AD^2 = CD^2

12.3^2 + 9.15^2 = CD^2

CD^2 = 235.0125

CD = square root of 235.0125 = 15.33cm

Hope this helps

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4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
4 years ago
What is the correct answer???
lapo4ka [179]

Answer:

Step-by-step explanation:

The given equation passes through the origin:

y-0 = \frac{1}{4} (x-0) + 4

The segment passes through the point (-2,6)

So the equation will become (y-6) = \frac{1}{4} (x+2) +4

3 0
3 years ago
Is this correct? I've done the answer just need to know if it's right?
kotegsom [21]
Yes your answer is correct
6 0
4 years ago
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