All categories

3 years ago

Help me out :) Last question I need

Mathematics

1 answer:

DerKrebs [107]3 years ago

5 0

Answer:

y=(-4/3)x-1

Step-by-step explanation:

Slope or m=-4/3

Y-intercept or b=-1

Putting in the standard equation y=mx+b

y=(-4/3)x+(-1)

y=(-4/3)x-1

You might be interested in

Val walks 2 3/5 miles each day.bill runs 10 once every 4 days.in 4 days.who covers the greater distance?

Mkey [24]

Answer: Val walks the greater distance. She walks 2/5 miles more than Bill. Hope this helps!

Step-by-step explanation:

6 0

3 years ago

27 in exponetial notation

docker41 [41]

Answer:

3^3

Step-by-step explanation:

3x3x3=27

7 0

3 years ago

A photography studio charges $50 that includes a sitting fee and 6 prints. Luigi increased his order to 11 prints and paid $65.

Effectus [21]

Answer:

Sitting fee - 32$

Step-by-step explanation:

This is a system of equations(let x represent the sitting fee)

x+6y=50

x+11y=65

You want to isolate the x variable - x+6y-6y=50-6y ; x = 50-6y

Input this into the 2nd equation: 50-6y+11y=65 ; 50+5y=65

Subtract 50 from both sides. 5y=15 (Divided 5y on both sides) ; y=3

Now that y = 3 input this into any equation I choose the 1st one.

x+6(3) = 50 ; x + 18 = 50 (Subtract 18 on both sides to get x)

x = 32

Prove: 32 + 6(3) = 50 ; 32+18 = 50 ; 50 = 50 True

7 0

3 years ago

Hi, can someone please help, and possibly explain the answer please.

mr_godi [17]

Answer:

$x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

Step-by-step explanation:

Quadratic formula: $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ when the equation is $0=ax^2+bx+c$

The given equation is $1=-2x+3x^2+1$ . Let's first arrange this so its format looks like $y=ax^2+bx+c$ :

$1=-2x+3x^2+1$

$1=3x^2-2x+1$

Subtract 1 from both sides of the equation

$1-1=3x^2-2x+1-1\\0=3x^2-2x+0$

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

I hope this helps!

8 0

3 years ago

Linda collects a random sample of 12 of the 98 Wilderness Club members’ ages. She makes an inference that most wilderness club m

mash [69]

The box plot that would confirm the inference that Linda made would have a minimum value of 20 and a maximum value of 40. Somewhere in the between is the mean. The box plot should have a confidence interval of 95% in order to have the inference valid.<span />

7 0

3 years ago