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postnew [5]
3 years ago
12

In the formula p=kt find t when k=36 and p=144

Mathematics
2 answers:
kow [346]3 years ago
8 0

Answer:

4

Step-by-step explanation:

As u know

p= kt

by putting the given values in the formula we get,

144=36×t

144/36= t

4= t

stepan [7]3 years ago
4 0

Answer:

t=4

Step-by-step explanation:

solve for t by deciding both sides by k.

then do 144/36 to get t.

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Divide both by a number that can go into both terms so it will be 5 . 
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3 years ago
Read 2 more answers
Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

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3 years ago
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Find the area of shaded region.
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Hey there mate ;),

Area of The shades region is <u>3098 m^2</u>

The solution is attached as picture. Please check.

<em>Answered</em><em> </em><em>by</em><em> </em><em>Benjemin</em>

6 0
2 years ago
46:34
Mashcka [7]

Answer:

The first 2

Step-by-step explanation:

First expression = -4+30-3 =23

Second expression = 8(10+4)= 112.

The others would lead to a negative number.

Remember negative times negative = positive

Negative times negative times negative = negative

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