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AlekseyPX
3 years ago
14

What is the measure of each angle in the Summer Triangle

Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

IDk

Step-by-step explanation:

I have no idea

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Four ninths plus nine eighteenths :]
goldenfox [79]

Answer:  17/18

In words, this is seventeen eighteenths

==========================================

Work Shown:

4/9 + 9/18

8/18 + 9/18 ... see note below

(8+9)/18

17/18

----------------

note: To go from 4/9 to 8/18, we multiply top and bottom by 2. So that's why 4/9 = 8/18.

The diagram below shows a visual representation of why 4/9 = 8/18.

In the top row, I've drawn out 9 rectangles of the same size. Then I've shaded 4 of the 9 rectangles to represent the fraction 4/9. In the bottom row, I've cut each of those 9 rectangles into two smaller equal pieces, so we have 9*2 = 18 rectangles now. Note how the shaded regions are the same size, so this shows 4 green regions doubles to 2*4 = 8 yellow regions; therefore 4/9 is the same as 8/18.

8 0
2 years ago
NEED HELP ASAP
KonstantinChe [14]

Answer:

All in the explanation.

Step-by-step explanation:

Since we will only be renting the car for one day it will only be a $50 dollar base fee. If we drive 192 miles and just rent it for one day the equation modeled will be $0.18(192) + 50 = 34.56 + 50 = $84.56 total.

3 0
2 years ago
The figure shows a line graph and two shaded triangles that are similar:
dlinn [17]

True:

3rd One

4th One

False: All of the others.

It's a straight line, so it is going to have straight qualities and straight inequalities throughout the graph.

8 0
3 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
2 years ago
What is the surface area of a sphere with a radius of 11cm? Use 3.14 for pi
vagabundo [1.1K]
I hope this helps you



Area=4.pi.r^2


Area =4.3,14.11^2


Area =1519
6 0
3 years ago
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