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alexandr402 [8]
3 years ago
14

What is the sum of X2-3x+7 and 3x2+5X-9

Mathematics
1 answer:
Pie3 years ago
6 0
x^2-3x+7+3x^2+5x-9=\ \ \ \  | combine\ like\ terms\\\\
4x^2+2x-2\\\\
Solution\ is\ 4x^2+2x-2.
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Tina must select and answer in any order three of seven
Leno4ka [110]

Answer:

Tina can select and answer the essay questions on her test in 35 ways.

Step-by-step explanation:

The order in which she chooses the questions is not important. For example, choosing questions 1, 3 and 7 is the same as choosing 7, 3 and 1. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Three questions from a set of 7. So

C_{7,3} = \frac{7!}{3!(7-4)!} = 35

Tina can select and answer the essay questions on her test in 35 ways.

6 0
3 years ago
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3 years ago
The coordinates of two vertices of a right triangle are shown on the grid.
miss Akunina [59]

Answer:

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Step-by-step explanation:

3 0
3 years ago
What is the approximate area of a sector given O= 56 degrees with a diameter of 12m?​
jeyben [28]

Area of sector is 17.584 meters

<em><u>Solution:</u></em>

Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m

Diameter = 12 m

Radius = Diameter / 2 = 6 m

An angle of  56 degrees is the fraction \frac{56}{360} of the whole rotation

A sector of a circle with a sector angle of 56 degrees is therefore also the fraction \frac{56}{360} of the circle

The area of the sector will therefore also be  \frac{56}{360} of the area

\text{ sector area } = \frac{56}{360} \times \pi r^2\\\\\text{ sector area } = \frac{56}{360} \times 3.14 \times 6^2\\\\\text{ sector area } = 17.584

Thus area of sector is 17.584 meters

3 0
3 years ago
Matrix A has 2 rows and 3 columns whereas matrix B has3 rows and 2 column
sergeinik [125]

Step-by-step explanation:

for any matrix multiplication number of columns of first matrix should be equal to number of rows of second matrix.

For AB

A has 3 columns and B has 3 rows so it matches . Hence can be multiplied.

For BA

B has 2 columns and A has 2 rows it also matches so can be multiplied

8 0
2 years ago
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