The answer is 22, good luck on you work
For y to not be a function of x, there needs to be an x-value that is paired with more than one y-value.
In terms of the sets, you need to find a set where the same x-value is used more than once in two (or more) different (x,y) pairs.
This occurs in the third set, where x=6 is used twice.
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>
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5k^3-8-4k^2+5k^2-2+3k^3
Group like terms:
5k^3+3k^3-4k^2+5k^2-8-2
Add similar elements:
5k^3+3k^3+k^2-8-2
Add similar elements:
8k^3+k^2-8-2
Subtract the numbers:
8k^3+k^2-10
Your Answer Is 8k^3+k^2-10
Plz mark me as brainliest :)
Answer:
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Step-by-step explanation:
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