When you get to the point where the width is larger than the length, you can stop because you have exhausted all the possibilities. The greatest area will be the rectangle that is closer in to a square than any of the others.
The answer is c.use pemdas❤️
<span>1. What number must multiply each side of the equation 2/5 x=10 to produce the equivalent equation x = 25? 4 5 5/2 1/5 2. Solve. -1/3 x=12 4 –36 –1/4 –4 3.Solve. 3|s| = 18 s = –6 or s = 6 s = 6 only s = –18 or s = 18 s = –6 only 4.Solve. x + 4 – 7x =...</span> show more Best Answer:<span> </span><span>C
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It is 18 because the radius is half the diameter and 9 x 2 = 18.
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
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b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
