1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
skad [1K]
3 years ago
13

What is the pOH of a solution with a pH of 8? 14 6 8 0

Chemistry
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

6.

Explanation:

<em>∵ pH + pOH = 14.</em>

<em />

<em>∴ pOH = 14 - pH = 14 - 8 = 6.</em>

You might be interested in
Determine the [OH-], pH, and pOH of a solution with a [H+] of 0.090 M at 25 °C. [OH-] = pH = pOH = 0 POH =
ValentinkaMS [17]

Answer : The concentration of OH^- ion, pH and pOH of solution is, 1.12\times 10^{-13}M, 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of H^+ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

pH=-\log [H^+]

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.090)

pH=1.05

The pH of the solution is, 1.05

Now we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-1.05=12.95

The pOH of the solution is, 12.95

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12.95=-\log [OH^-]

[OH^-]=1.12\times 10^{-13}M

The OH^- concentration is, 1.12\times 10^{-13}M

5 0
2 years ago
Read 2 more answers
Describe the process of sublimation in terms of heat
Lisa [10]

Sublimation is like the changing a solid into a gas without passing through the liquid phase. To sublime a substance, a specific energy has be transferred to the via heat or work.

plz mark me as brainliest if this helped :)

7 0
3 years ago
How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?
pashok25 [27]

C3H8 + 5O2 ------> 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol


x=(1.82*5)/1 = 9.10 mol CO2

4 0
3 years ago
Each astronaut produces 8.8 × 102 g CO2 per day that must be removed from the air on the shuttle. If a typical shuttle mission i
suter [353]

The reaction of removing CO2 using LiOH is the following:

2 LiOH + CO2 -----> Li2CO3 + H2O

By solving the amount of CO2 the LiOH can scrub:

(3.50 × 10^4 g LiOH) (1 mol LiOH/ 24 g LiOH) ( 1 mol CO2 / 2 mol LiOH) ( 44 g CO2 /1 mol CO2) = 32, 083.33 g CO2 it can scrub

<span>Since number of astronaut = 32, 083.33 g / 9 (8.8 × 10^2) = 4 astronaut</span>

7 0
3 years ago
Read 2 more answers
Where does radioactivity come from?
Aleks04 [339]

Radioactivity comes from unstable atoms of certain elements. Radioactivity consists of alpha radiation (2 protons and 2 neutrons), beta radiation (1 electron), or gamma radiation (Electromagnetic photons).

8 0
3 years ago
Read 2 more answers
Other questions:
  • How much heat is needed to raise the temperature of a 5.0 gram block of aluminum from 22.0°c to 37.0°c?
    15·2 answers
  • When more organisms move into an ecosystem and use more resources, the result is
    13·2 answers
  • The process of _______ begins in the mouth, where for is ground into small pieces.
    12·2 answers
  • On the basis of the solubility curves shown above, the greatest percentage of which compound can be recovered by cooling a satur
    8·2 answers
  • What is the formula of arsenic hexabromide?
    10·1 answer
  • After creating a Beer's Law plot using standard solutions of Q, you determined the slope of Beer's Law to be 0.543 M-1. Your unk
    12·1 answer
  • Classify the following reaction:2h2o 2h2 o2
    9·2 answers
  • A forester mixes gasoline and oil to make 6 gallons of mixture for his two-cycle chain-saw engine. This mixture is 60 parts gaso
    9·1 answer
  • In a balanced equation, the number of each type of atom on the reactant side ____________ the number of each type of atom on the
    14·1 answer
  • If you have 90L of water, what is the volume?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!