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skad [1K]
3 years ago
13

What is the pOH of a solution with a pH of 8? 14 6 8 0

Chemistry
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

6.

Explanation:

<em>∵ pH + pOH = 14.</em>

<em />

<em>∴ pOH = 14 - pH = 14 - 8 = 6.</em>

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The tsunami walls at Miyako were high enough to hold back the water.<br> True<br> False
V125BC [204]
False the tsunami was up to 128 ft tall (39 meters) and flooded the city.
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3 years ago
50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter
cricket20 [7]
  • Work done=50J
  • Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

  • Hence the internal energy would increase by 21J

Option B is correct

3 0
3 years ago
Read 2 more answers
The best material to be used in making cooking pots handles is made of: a. Polypropylene b. Bakelite c. Rubber d. Polyethylene
frutty [35]

Answer:

b. Bakelite

Explanation:

Bakelite -

Bakelite is a form if plastic , and is the very first plastic synthesized .

The handles of the cooking utensils are used to hold the utensil firmly , and hence need not turn hot while cooking , and need to be strong enough to take care of the food .

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Hence , bakelite is used for making the handle.

6 0
3 years ago
Is pentacosane a molecular compound?
jekas [21]

Answer:

Yes

Explanation:

A molecular compound is that one which is composed of molecules formed by atoms of two or different elements. A pentacosane is an alkaline made of unbranched chain of 25 carbons atoms. It has applications in plant metabolite. The molecular formula of pentacosane is C₂₅H₅₂

7 0
3 years ago
The radioisotope phosphorus-32 is used in tracers for measuring phosphorus uptake by plants. The half-life of phosphorus-32 is 1
Harman [31]

Answer:

54 days

Explanation:

We have to use the formula;

0.693/t1/2 =2.303/t log Ao/A

Where;

t1/2= half-life of phosphorus-32= 14.3 days

t= time taken for the activity to fall to 7.34% of its original value

Ao=initial activity of phosphorus-32

A= activity of phosphorus-32 after a time t

Note that;

A=0.0734Ao (the activity of the sample decreased to 7.34% of the activity of the original sample)

Substituting values;

0.693/14.3 = 2.303/t log Ao/0.0734Ao

0.693/14.3 = 2.303/t log 1/0.0734

0.693/14.3 = 2.6/t

0.048=2.6/t

t= 2.6/0.048

t= 54 days

3 0
3 years ago
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