Answer:
There is 18.8% lithium by mass in second sample
Explanation:
Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-
Let's assume weight of first sample is x g
So, 100 g of sample contains 18.8 g of lithium
Hence, x g of sample contains 
g of lithium
Now, the second sample has weight equal to 2x g
So, 2x g of sample contains 
g of lithium
So, % lithium by mass in second sample = 
% = 18.8%
The question is in complete, the complete question is:
Which element has an outer electron configuration of s
2
p4
?
(A) Ca (B) Cr (C) Ge (D) Se
Answer:
(D) Se
Explanation:
The outer electronic configuration of an atom reflects the group to which it belongs in the periodic table. Each group has its unique outermost electron configuration and number of electrons found in the outermost shell of the atoms of elements in the group.
s
2
p4 is the unique outermost electron configuration of group 16 elements. Group 16 elements have six electrons in their outermost shell. If we consider the options, only Se is a member of group 16. Hence it is only Se that has the outermost electron configuration s
2
p4
.
Answer:
we will take a 100g sample of this solution for our convenience
so , there is 15 g kBr in this 100g solution
we know that molality is the number if moles of solute / mass of solvent in kg
we need to find the number of moles in 15g kBr
no of moles = 15/119 s
moles = 0.126 moles/ 100g
multiplying both the numerator and the denominator by 10 to get 1 kg in denominator
= 1.26 moles / 1 kg
Hence, the molality is 1.26
would appreciate a brainliest
Answer:
Ionic bonds are stronger than covalent bonds
Answer:
This is a single replacement reaction because I replaces Br.
