Answer:
80.1 grams
Explanation:
Find the molar mass of CH3OH first by using the periodic table values.
12.011 g/mol C + (1.008*3 g/mol H) + 15.999g/mol O + 1.008 g/mol H
=32.042 so that is the molar mass
Now that you have 2.50 moles of CH3OH, you can calculate the mass in g
2.50molCH3OH * (32.042g CH3OH / 1 mol CH3OH) = 80.105
32.042g / 1 mol is the same as 32.042 g/mol
Since there are 3 sig figs in the problem (2.50 has 3 sig figs), you round to 80.1 g CH3OH
Given :
Mass of O₂, m = 25.43 g.
To Find :
How many liters of gas will you have at STP.
Solution :
Molecular mass of O₂, M.M = 2 × 16 gram/mole
M.M = 32 gram/mole
Number of moles is given by :
n = m/M.M
n = 25.43/32 mole
n = 0.79 mole
Hence, this is the required solution.
I belive its D if not right sorry.
(4) chemical energy to electrical energy is the correct answer.
Hope this helps~
