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3 years ago

8

A hydrogen electron is elevated from level 1 to level 2. Another electron is elevated from level 2 to level

1 answer:

BaLLatris [955]3 years ago

5 0

Answer: level 2 to level 4

Explanation:

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Balance the following redox equation in acidic solution using the smallest integers possible and select the correct coefficient

romanna [79]

Answer:

Coefficient of $H^{+}(aq)$ is more than 4

Explanation:

Oxidation: $Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)$

Balance charge: $Sn^{2+}(aq)-2e^{-}\rightarrow Sn^{4+}(aq)$ ......(1)

Reduction: $Cr_{2}O_{7}^{2-}(aq)\rightarrow Cr^{3+}(aq)$

Balance Cr: $Cr_{2}O_{7}^{2-}(aq)\rightarrow 2Cr^{3+}(aq)$
Balance O and H in acidic medium: $Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)$
Balance charge: $Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)+6e^{-}\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)$ .......(2)

$[3\times Equation-(1)]+Equation(2)$ gives balanced equation:

$3Sn^{2+}(aq)+Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 3Sn^{4+}(aq)+2Cr^{3+}(aq)+7H_{2}O(l)$

So coefficient of $H^{+}(aq)$ is more than 4

3 0

2 years ago

Give the postional isomers of 2 halopropane<br>(CH3)2CH

s344n2d4d5 [400]

Give the positional isomers of 2 halopropane

(CH3)2CH

answer:

is in file download it

6 0

2 years ago

Electron transport is the process by which ________. Multiple Choice fatty acids break apart to form acetyl-CoA NADH + H+ and FA

Serggg [28]

Answer:

Electron transport is the process by NADH + H+ and FADH2 are converted to NAD+ and FAD, donating electrons and hydrogen ions to oxygen

Explanation:

3 0

3 years ago

Do humans really have a third eye

Dominik [7]

Well I wouldn't quite call it a third eye but yes we have the ability to see things if we connect to our inner selves

6 0

3 years ago

Read 2 more answers

Calculate the percentage by mass of oxygen in trioxonitrate (v) acid, (HNO3). [ H=1, N=14, O=16]

Vadim26 [7]

Answer:

Percentage by mass of oxygen = 76.20% (Approx)

Explanation:

Given:

HNO3

H=1, N=14, O=16]

Find:

Percentage by mass of oxygen

Computation:

HNO3

Total mass = 1 + 14 + 3(16)

Total mass = 63

Mass of oxygen = (3)(16) = 48

Percentage by mass of oxygen = [48/63]100

Percentage by mass of oxygen = 76.20% (Approx)

4 0

3 years ago