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lozanna [386]
3 years ago
13

Use the grouping method to factor x^3 + x^2 + 5x + 5

Mathematics
2 answers:
makvit [3.9K]3 years ago
6 0
X^2(x+1)+5(x+1)

(x^2+5)(x+1)
the answer is a
Anuta_ua [19.1K]3 years ago
4 0

Answer:

(x + 1) (x^2 + 5)

Step-by-step explanation:

Simplify the following:

x^3 + x^2 + 5 x + 5

Factor terms by grouping. x^3 + x^2 + 5 x + 5 = (x^3 + x^2) + (5 x + 5) = x^2 (x + 1) + 5 (x + 1):

x^2 (x + 1) + 5 (x + 1)

Factor x + 1 from x^2 (x + 1) + 5 (x + 1):

Answer:  (x + 1) (x^2 + 5)

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Answer:

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Step-by-step explanation:

Your intervals are x=-2, and x=0. In this case, x=-2 will be a, and x=0 will be b.

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Then, f(0)

f(0)= 1-3(0)^2\\f(0) = 1-3(0)\\f(0) = 1

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Average = \frac{(1)-(-11)}{(0)-(-2)} \\\\

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8 0
2 years ago
The following equation will have two solutions, y = x2 - 2x - 15?<br> True<br> False
motikmotik
The answer would be False.
3 0
3 years ago
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Westkost [7]

Answer:

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Step-by-step explanation:

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3 years ago
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