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Julli [10]
3 years ago
9

PLEASE HELP

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

We want to identify different things on the given graph.

The solutions are:

A) (3, -1)

B) x = 4

C) x = y^2 + 2y + 4

D) x ⇒ ∞, y ⇒ ∞

   x⇒3, y⇒ -1

A) The first thing we want to identify is the vertex, we could say that a vertex is a point of symmetry. (like the minimum/maximum of a parabola). Here we clearly do not have a point of symmetry, as we only have half of a parabola, but if it was a complete one, the vertex would be at the blue point, in (3, -1)

B) This is the point where the graph intercepts the x-axis, x = 4.

C) we want to write the equation, we start with the general parabola, this time as a function of y:

x = a*y^2 + b*y + c

Remember that the x-itercept is at x = 4. then c = 4.

x = a*y^2 + b*y + 4

The y-value of the vertex is -1, while the general y-value of the vertex is:

y = -b/2a = -1

And evaluating the equation in this value, gives us:

x = a*(-1)^2 + b*-1 + 4 = 3

Then we have two equations:

-b/2a = -1

a + -b + 4 = 3

We can rewrite the first one as:

-b = -2a

b = 2a

Now we can replace this on the other equation:

a - 2a + 4  =3

-a + 4 = 3

-a = 3 - 4 = -1

a = 1

And b = 2a = 2*1 = 2

Then the equation of the parabola is:

x = y^2 + 2y + 4

D) We can see that as x grows, y increases, so we can say that:

x ⇒ ∞, y ⇒ ∞

And for the other limit we can see that as x tends to 3, y tends to -1, then:

x⇒3, y⇒ -1

If you want to learn more, you can read:

brainly.com/question/21685473

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