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3 years ago

Find the area of the figure shown:

Mathematics

2 answers:

vladimir2022 [97]3 years ago

6 0

Answer:

answer is option b 70

Step-by-step explanation:

A=b×h = A= 14×5= 70

ivanzaharov [21]3 years ago

6 0

Answer:

option b 70

Step-by-step explanation:

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What is the volume of this rectangular prism?

Natalija [7]

Answer:

Step-by-step explanation:

To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height. The volume is expressed in cubic units.

The given rectangular prism has sides that have values of 3/2 (Decimal: 1.5), 4, and 1/2 (Decimal: 0.5).

So using the formula:

L × W × H

We can calculate:

V=whl=4·1.5·0.5=3

6 0

2 years ago

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On a certain function machine, an input of 3 has an output of -6. An input of -2 has an output of 4. An input of 0 has an output

mars1129 [50]

Answer:

The answer is multiplying by -2

Step-by-step explanation:

8 0

3 years ago

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Find the value of x and the value of y.

mezya [45]

Answer i pick is A. got to MULTIPLE BY 2 FOR X

3 0

3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

3. The three salespeople for a local advertising firm are Lola, Ahmed, and Tommy. Lola sold $2030 in ads, Ahmed sold $1540, and

Salsk061 [2.6K]

3. (a)

Add the three totals.

Total sales for all three: $2030 + $1540 + $1800 = $5370

Now divide each person's sales by the total sales to find each person's fraction of the sales.

Lola: 2030/5370
Ahmed: 1540/5370
Tommy: 1800/5370

3. (b)

Multiply each fraction from part (a) by $100.

Lola: 2030/5370 * $100 = $37.80
Ahmed: 1540/5370 = $28.67
Tommy: 1800/5370 = $33.52

6 0

3 years ago