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Ray Of Light [21]

4 years ago

13

❌what number would you have to add to both sides to complete the square?

1 answer:

Verdich [7]4 years ago

5 0

Hello,

Let's to remember,

To the perfect square:

X^2 +12x = -6

We would have to add 6^2

Because,

X^2 + 2.(6X) = -6

As (x+k) = x^2 +2xk +k

And,

2xk = 2.6x

xk = 6x

K = 6

Then,

(X+k)^2 = x^2 + 2xk+k^2

= x^2+2.x.6+6^2

= x^2+6x+36

We would to add 36, and would stay:

X^2 + 6X = -6

x^2 +6x + 36 = -6 +36

X^2 +2.6x +6^2 = 30

(X+6)^2 = 30

Answer is the letter A)

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<em>The question is incomplete:</em>

<em>The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31. </em>

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The significance level is α=0.05.

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$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

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$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

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