The slope is 4/3 & the y- int is 2. the equation is y= 4/3x+2
Answer:
Step-by-step explanation:
Let's do this properly:
Area of trapezoid = average length times height.
Here,
Area = (1/2)(8 cm + 14 cm)(8 cm), or
= (11 cm)(8 cm) = 88 cm^2
It appears that Tina forgot to divide the sum of 14 cm and 8 cm by 2. Thus, her answer is twice as large as it should be.
The identity in question is
cos(a - b) = cos(a) cos(b) + sin(a) sin(b)
so that
cos(a - b) = 12/37 cos(a) + 3/5 sin(b)
Since both a and b lie in the first quadrant, both cos(a) and sin(b) will be positive. Then it follows from the Pythagorean identity,
cos²(x) + sin²(x) = 1,
that
cos(a) = √(1 - sin²(a)) = 4/5
and
sin(b) = √(1 - cos²(b)) = 35/37
So,
cos(a - b) = 12/37 • 4/5 + 3/5 • 35/37 = 153/185
Y= (2×2)- 4 +3/4 = 12/4 or 3 that I'd the best of my
