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Eddi Din [679]
3 years ago
7

PLEASE SOLVE CORRECTLY!!! I HAVE CHECKED THE ANSWER AND IT SAYS $64.67 BUT I DON'T KNOW THE PROCESS TO GET THAT ANSWER!!! HELP!!

! PLEASE ANSWER QUICKLY!!!!
Question: If you have a beginning balance of $139.50 and write checks for $12.57, $24.95, and $36.86, what will be your ending balance if your bank charges $0.15 per check?
Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

First determine how much is subtracted from the account

12.57+24.95+36.86 =74.38

They charge .15 per check=3*.15 = .45

Subtract the amounts of the checks and the check fees

139.50-74.38-.45 =64.67

Nikitich [7]3 years ago
5 0

Answer:

$64.67

Step-by-step explanation:

Expenses: 12.57 + 24.95 + 36.86 + (3×0.15)

Expenses: $74.83

Balance = 139.5 - 74.83

Balance: $64.67

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\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}

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\textsf{Let }\:u=\sin (2x) \implies \dfrac{\text{d}u}{\text{d}x}=2 \cos (2x)

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\begin{aligned}\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\sin (2x)- \int \dfrac{1}{2}e^{-2x} \cdot 2 \cos (2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\sin (2x)- \int e^{-2x} \cos (2x)\:\text{d}x\end{aligned}

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\begin{aligned}\implies \displaystyle -\int e^{-2x}\cos(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\cos(2x)- \int \dfrac{1}{2}e^{-2x} \cdot -2 \sin(2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x\end{aligned}

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