162/(6(7-4)^2)
pemdas
parenthasees inner first
so 7-4 is forst
7-4=3
162/(6(3)^2)
then exponents
3^2=9
162/(6(9))
multiplication
6 times 9=54
162/(54)=3
Answer:
The price of an adult ticket is $9 and the price of a student ticket is $6
Step-by-step explanation:
Create a system of equations where x is the price of an adult ticket and y is the price of a student ticket:
2x + 7y = 60
3x + 11y = 93
Solve by elimination by multiplying the top equation by 3 and the bottom equation by -2, to cancel out the x terms:
6x + 21y = 180
-6x - 22y = -186
Add them together:
-y = -6
y = 6
Then, plug in 6 as y into one of the equations to solve for x:
2x + 7y = 60
2x + 7(6) = 60
2x + 42 = 60
2x = 18
x = 9
So, the price of an adult ticket is $9 and the price of a student ticket is $6
Would this work? Hope it helps
Answer:
111 / 190
Step-by-step explanation:
Total biscuits = 20
Plain, P = 12
Chocolate, C = 5
Currant, K = 3
Assume without replacement :
Probability that biscuit are of the same type :
P(plain) :
12 / 20 * 11 / 19 = 132 / 380
P(chocolate) :
5/ 20 * 4 / 19 = 20/ 380
P(currant) :
3/20 * 2 /19 = 6 / 380
Therefore,
Probability that biscuit is of the same type :
P(plain) + P(chocolate) + P(currant)
132/380 + 20/380 + 6/380
158 / 380 = 79 / 190
Therefore, probability that biscuit aren't of the same type :
1 - P(biscuit is of same type)
1 - 79/190
(190 - 79) / 190
111 / 190