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4 years ago

In the 200meter race

1 answer:

6 0

-Average acceleration is (v2-v1)/(t2-t1). And we are told that he has constant acceleration of 1.5. Since acceleration is constant, constant=average. So:

a=(v2-v1)/(t2-t1) which in this case is:

(9-2)/t=1.5

7=1.5t

t=14/3 seconds

t= 4 2/3 seconds

You might be interested in

9000 for 5 years at 4.5% compounded monthly

tatuchka [14]

I think its 9000(1.045)^5. Hope this helps. That equals $11,215.60, or rounded to the nearest dollar, $11,215.

7 0

3 years ago

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

REY [17]

The question is incomplete as the cost price isn't given. However, taking the cost price as x :

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

Let :

Cost price when new = x

Cost price when sold = 4/5 * cost price when new

Cost when sold = 4/5 of x = 4x/5

Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)

Hence,

Amount of money lost on the car = (x - 4x/5)

x - 4x/5 = (5x - 4x) / 5 = x / 5

To obtain the exact price, kindly input the omitted cost when new for x.

7 0

3 years ago

Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu

Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

$1:\sqrt{3}:2$

Since Hypotenuse = 12 cm

So, it becomes,

$2x=12\\\\x=\dfrac{12}{2}=6$

So, Base would be

$x=6\ cm$

and Perpendicular would be

$\sqrt{3}x=6\sqrt{3}$

So, Area common to the both triangles would be

$\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177$

Hence, the area common to both triangle is 31.77 sq. cm.

4 0

3 years ago

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up. The

Nikolay [14]

The length of the ladder nearest hundredth of a foot is 23 feet.

We have given that,

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up.

The ladder makes an angle of $77^{\circ}$ the ground.

<h3>What is the sin ratio?</h3>

$sin(\theta)=\frac{perpendicular \ side}{hypotenous}$

Therefore we get,

$\implies\frac{22}{H} =sin(77)$

$\implies H=22/sin(77)$

$\implies 22.59ft\\\\=23ft$

Therefore, The length of the ladder nearest hundredth of a foot is 23 feet.

To learn more about the trigonometric ratio visit:

brainly.com/question/24349828

#SPJ1

7 0

2 years ago

Two numbers have an LCM = 48 and a GCF = 8. One of the numbers is 16.<br>What is the other number?

alexira [117]

Answer:

Step-by-step explanation:

7 0

3 years ago