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Sedaia [141]
2 years ago
14

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up. The

ladder makes an angle of 77^{\circ} ∘ with the ground. Find the length of the ladder. Round your answer to the nearest hundredth of a foot if necessary.
Mathematics
1 answer:
Nikolay [14]2 years ago
7 0

The length of the ladder nearest hundredth of a foot is 23 feet.

We have given that,

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up.

The ladder makes an angle of 77^{\circ}  the ground.

<h3>What is the sin ratio?</h3>

sin(\theta)=\frac{perpendicular \ side}{hypotenous}

Therefore we get,

\implies\frac{22}{H} =sin(77)

\implies H=22/sin(77)

\implies 22.59ft\\\\=23ft

Therefore, The length of the ladder nearest hundredth of a foot is 23 feet.

To learn more about the trigonometric ratio visit:

brainly.com/question/24349828

#SPJ1

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Peyton's field hockey team wins 4 games out of every 7 games played. Her team lost 9 games. How many games did Peyton's team pla
andre [41]

Answer:

Games played= 21 games

Step-by-step explanation:

Giving the following information:

Peyton's field hockey team wins 4 games out of every 7 games played.

We know that Peyton's team loses 3 games out of 7.

So if the team lost 9 games, the proportion is completed 3 times.

Games played= 3*7= 21 games

4 0
3 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
3 years ago
Divide and simplify.
balandron [24]
The last one is the correct one.


8 0
3 years ago
Write the correct equation to represent this situation. Alex's father is
harina [27]
35+1m

M= number of movies he ends up buying.
8 0
3 years ago
I NEEEDDDD HELP PLZZZZZZZZZZZZZZZZZZZZZZZZZ
Montano1993 [528]

Answer:

80 cm

Step-by-step explanation:

The diagonals divide the rhombus into four congruent triangles.  The height of each triangle is 18/2 = 9, and the hypotenuse is 41.  Using Pythagorean theorem, the width of each triangle is:

c² = a² + b²

41² = 9² + x²

x = 40

Therefore, the longer diagonal is 2×40 = 80.

5 0
2 years ago
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