Check the forward differences of the sequence.
If
, then let
be the sequence of first-order differences of
. That is, for n ≥ 1,

so that
.
Let
be the sequence of differences of
,

and we see that this is a constant sequence,
. In other words,
is an arithmetic sequence with common difference between terms of 2. That is,

and we can solve for
in terms of
:



and so on down to

We solve for
in the same way.

Then



and so on down to


The answer is E hope this helps
Divide the denominator by the numerator
Answer:
<em>Sam is 30 years old, and Harry is 10 years old.</em>
Step-by-step explanation:
Let us assume that the age of Sam is x and the age of Harry is y.
Sam is currently is three times Harry's age.
So,
----------------------1
Sam's age is also 10 more than twice Harry's age.
so,
---------------2
Subtracting 2 from 1, we get



putting this in equation 1,

Therefore, Sam is 30 years old, and Harry is 10 years old.
The answer to the question is b