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3 years ago

What is the answer 6a=5/7

Mathematics

1 answer:

sergejj [24]3 years ago

6 0

Divide both sides by 6, aka times both sides by 1/6
a=5/7 times 1/6
a=5/42

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Here is Triangle A. Lin created a scaled copy of Triangle A with an area of 72 square units. C. What is the length of bottom sid

satela [25.4K]

Answer:

The length of bottom side of the scaled copy is 12 u

Step-by-step explanation:

To solve this problem we have to know that to calculate the area of a triangle we use the following formula

a = area

b = base

h = height

a = b * h

In the triangle A the base and the height are equal to 3

b = h

Now that we know that b & h we can calculate the base of the scaled copy

72 u² = b * b

72 u² = (b)²

√(72 u²) = b

12 u = b

The length of bottom side of the scaled copy is 12 u

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3 years ago

in the final event of a track meet, 6 runners run a 100 meter dash. A) How many possible arrangements are there for the medal wi

ohaa [14]

6 runners, 3 medals, how many ways to give them? well, runner say 2 could get gold or not, bronze or not and silver or not, and so can any other runnner, and the order "does matter", it makes a distinction, thus, is a Permutation

$\bf _nP_r=\cfrac{n!}{(n-r)!}\qquad \qquad _6P_3=\cfrac{6!}{(6-3)!}$

3 0

3 years ago

Read 2 more answers

Today the temperature is 0 degrees Fahrenheit. The temperature rose

VladimirAG [237]

Answer: -11 degrees Fahrenheit

Step-by-step explanation:

3 0

3 years ago

Please help as soon as possible.

aniked [119]

Answer:

C = 37.6991

Step-by-step explanation:

The equation for the circumference of a circle is given: C = π · d

where, d is the diameter of the circle.

Plug in the value of d = 12 and use the π button on the calculator.

C = π · 12

C = 37.6991

5 0

3 years ago

Read 2 more answers

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bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

2 years ago