Use the information to answer the question. Sabrina walked from her home to the library she stopped to pick up a book, and then
she walked home. Sabrina's Walk 2.0- 1.5 Distance from Home (miles) 0.5- 10 20 30 40 50 60 70 80 Time (minutes) Between which times was Sabrina at the brary Enter the answer in the boxes. minutes to minutes
1 answer:
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Answer:
Population mean = 7 ± 2.306 ×
Step-by-step explanation:
Given - A university researcher wants to estimate the mean number
of novels that seniors read during their time in college. An exit
survey was conducted with a random sample of 9 seniors. The
sample mean was 7 novels with standard deviation 2.29 novels.
To find - Assuming that all conditions for conducting inference have
been met, which of the following is a 94.645% confidence
interval for the population mean number of novels read by
all seniors?
Proof -
Given that,
Mean ,x⁻ = 7
Standard deviation, s = 2.29
Size, n = 9
Now,
Degrees of freedom = df
= n - 1
= 9 - 1
= 8
⇒Degrees of freedom = 8
Now,
At 94.645% confidence level
α = 1 - 94.645%
=1 - 0.94645
=0.05355 ≈ 0.05
⇒α = 0.5
Now,
= 0.025
Then,
= 2.306
∴ we get
Population mean = x⁻ ± ×
= 7 ± 2.306 ×
⇒Population mean = 7 ± 2.306 ×
Answer:
0.7738 = 77.38% probability that an incorrect message is received.
Step-by-step explanation:
For each bit, there are only two possible outcomes. Either it is corrupted, or it is not. The probability of a bit being corrupted is independent of any other bit. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
5% probability a bit is sent incorrectly:
This means that
Message of length 5
This means that
What is the probability that an incorrect message is received?
This is the probability of at least one incorrect bit, which is:
In which
0.7738 = 77.38% probability that an incorrect message is received.