The numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Since a furniture company has 480 board ft of teak wood and can sustain up to 450 hours of labor each week, and each chair produced requires 8 ft of wood and 12 hours of labor, and each table requires 20 ft of wood and 15 hours of labor, to determine, if a chair yields a profit of $ 65 and a table yields a profit of $ 90, what are the numbers of chairs and tables that should be produced each week in order to maximize the company's profit, the following calculation should be done:
16 chairs; 24 tables
Time used = 16 x 12 + 24 x 15 = 192 + 360 = 552
Wood used = 16 x 8 + 24 x 20 = 128 + 480 = 608
15 chairs; 18 tables
Time used = 15 x 12 + 18 x 15 = 180 + 270 = 450
Wood used = 15 x 8 + 18 x 20 = 120 + 360 = 480
12 chairs; 28 tables
Time used = 12 x 12 + 28 x 15 = 144 + 420 = 564
Wood used = 12 x 8 + 28 x 20 = 96 + 540 = 636
18 chairs; 20 tables
Time used = 18 x 12 + 20 x 15 = 216 + 300 = 516
Wood used = 18 x 8 + 20 x 20 = 144 + 400 = 544
Therefore, the only option that meets the requirements of time and wood used is that of 15 chairs and 18 tables, whose economic benefit will be the following:
15 x 65 + 18 x 90 = X
975 + 1,620 = X
2,595 = X
Therefore, the numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Answer:
(-6,-4)
Step-by-step explanation:
The first endpoint of the line is (-6,8), we can call
x_1 = -6
and
y_1 = 8
Let the last endpoint have coordinates (x_2,y_2)
Also, the midpoint formula is:
(x_1+x_2)/2 , (y_1+y_2)/2
Now, plugging these values is the formula, we get:
(-6+x_2)/2 = -6
-6+x_2=-12
x_2=-12+6 = -6
x_2 = -6
Also
(8+y_2)/2=2
8+y_2=4
y_2=4-8=-4
y_2 = -4
The coordinates of the other endpoint is (-6,-4)
Answer
Sol: The correct answer is b. three planes that contain point B are ABD, AEF and DHF.
