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Brut [27]
3 years ago
9

Use the information to answer the question. Sabrina walked from her home to the library she stopped to pick up a book, and then

she walked home. Sabrina's Walk 2.0- 1.5 Distance from Home (miles) 0.5- 10 20 30 40 50 60 70 80 Time (minutes) Between which times was Sabrina at the brary Enter the answer in the boxes. minutes to minutes​

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0

Answer:

30 minutes to 40 minutes.

Step-by-step explanation:

From the graph attached,

Distance of Sabrina from her home has been given on y-axis and time taken is on x-axis.

Sabrina's walked 2 miles to reach the library in the duration = 30 - 0

= 30 minutes

She stayed at the library from 30 minutes to 40 minutes (Represented by the straight horizontal line).

Then the third segment represents the journey of Sabrina from library to home.

Therefore, Sabrina was at the library between 30 minutes to 40 minutes.

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Is -6.743743… a rational or irrational number?
yaroslaw [1]

It's rational because it contains a repeating digit pattern, 743 (first option).

In particular, if

<em>x</em> = -6.743743…,

then

1000<em>x</em> = -6,743.743743… .

Subtracting, we can eliminate the trailing end and solve for <em>x</em> exactly:

1000<em>x</em> - <em>x</em> = -6,743.743743… - (-6.743743…)

999<em>x</em> = -6,737

<em>x</em> = -6,737/999

8 0
3 years ago
A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

3 0
3 years ago
Read 2 more answers
What is the value of 63,108 dividend by 72
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Suppose we are sending a digital signal which is a string of 0s and 1s of length five. (Example stringsare 00101, 11000, 10101 a
masha68 [24]

Answer:

0.7738 = 77.38% probability that an incorrect message is received.

Step-by-step explanation:

For each bit, there are only two possible outcomes. Either it is corrupted, or it is not. The probability of a bit being corrupted is independent of any other bit. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% probability a bit is sent incorrectly:

This means that p = 0.05

Message of length 5

This means that n = 5

What is the probability that an incorrect message is received?

This is the probability of at least one incorrect bit, which is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738

0.7738 = 77.38% probability that an incorrect message is received.

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3 years ago
If the point (-7, -3) is a reflection across the x-axis, its pre-image is at (-7, 3). True /false
Evgen [1.6K]

Answer:false

Step-by-step explanation:

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