Answer:
y=2.50x+4.00
over here the gradient is 2.50
and the y-intercept is 4.00
so in the first one, start Drawing the line from 4 on y axis
So a few points would be: (0,4) (1,6.5) (2,9) (3,11.5) (4,14)
second equation...
y=2.00x+5.00
gradient is 2.00
and y intercept is 5
so draw the line from 5 on the y axis
A few points would be: (0,5) (1,7) (2,9) (3,11) (4,13)
As you see, I got the common point (2,9) in both, so they intersect at (2,9)
<u><em>Answer:</em></u>
slope =
<u><em>Explanation:</em></u>
<u>The general form of the linear line is:</u>
y = mx + c
where:
m is the slope
c is the y-intercept
<u>The given equation is:</u>
7x + 4y = 20
<u>We will start by putting the equation in the general form:</u>
7x + 4y = 20
4y = -7x + 20
y =
<u>Now, comparing our equation with the general form, we would find that:</u>
m = slope =
c = y-intercept = 5
Hope this helps :)
Answer:
The probability that the product will be successfully launched given that the market test result comes back negative is 0.30.
Step-by-step explanation:
Denote the events provided as follows:
<em>S</em> = a product is successfully launched
<em>P</em> = positive test market result
The information provided is:
P (S) = 0.60
P (P | S) = 0.80
P (P | S') = 0.30
Then,
P (P' | S) = 1 - P (P | S) = 1 - 0.80 = 0.20
P (P' | S') = 1 - P (P | S') = 1 - 0.30 = 0.70
Compute the probability of positive test market result as follows:
The probability of positive test market result is 0.60.
Then the probability of negative test market result is:
P (P') = 1 - P (P)
= 1 - 0.60
= 0.40
Compute the probability that the product will be successfully launched given that the market test result comes back negative as follows:
Thus, the probability that the product will be successfully launched given that the market test result comes back negative is 0.30.
Answer:
True
Step-by-step explanation:
we know that
A non-negative number is a real number greater than or equal to zero
In this problem
we have
The solution of the inequality is all real numbers greater than or equal to zero [0,∞)
Therefore
express a non-negative number in symbols