Given:
Lilly starts hiking along a trail at 3 miles per hour.
Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.
lilly walked 2 miles before Dave started hiking.
To find:
Whether he will catch up to her and write an equation.
Step-by-step explanation:
Let the number of hours when both are hiking be h.
lilly walked 2 miles before Dave started hiking at 3 miles per hour.
Lilly hiking = 2+3h
Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.
Dave hiking = 3.5 h
He will catch her if hiking distance of both are equal.
![2+3h=3.5h](https://tex.z-dn.net/?f=2%2B3h%3D3.5h)
Subtract 3h from both sides.
![2=3.5h-3h](https://tex.z-dn.net/?f=2%3D3.5h-3h)
![2=0.5h](https://tex.z-dn.net/?f=2%3D0.5h)
Divide both sides by 0.5.
![\dfrac{2}{0.5}=h](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B0.5%7D%3Dh)
![4=h](https://tex.z-dn.net/?f=4%3Dh)
Therefore, Dave will catch her after 4 hours.