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Vladimir79 [104]
3 years ago
7

Lilly starts hiking along a trail at 3 miles per hour. Dave starts hiking the same trail from the same starting point at 3.5 mil

es per hour. If lilly walked 2 miles before Dave started hiking , will he catch up to her ? write a equation ​
Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0

Given:

Lilly starts hiking along a trail at 3 miles per hour.

Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.

lilly walked 2 miles before Dave started hiking.

To find:

Whether he will catch up to her and write an equation.

Step-by-step explanation:

Let the number of hours when both are hiking be h.

lilly walked 2 miles before Dave started hiking at 3 miles per hour.

Lilly hiking = 2+3h

Dave starts hiking the same trail from the same starting point at 3.5 miles per hour.

Dave hiking = 3.5 h

He will catch her if hiking distance of both are equal.

2+3h=3.5h

Subtract 3h from both sides.

2=3.5h-3h

2=0.5h

Divide both sides by 0.5.

\dfrac{2}{0.5}=h

4=h

Therefore, Dave will catch her after 4 hours.

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John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21 About how far does
Agata [3.3K]

Answer:

John ski down the mountain is 1285.37 feet.

Step-by-step explanation:

Given : John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21.

To find : About how far does  John ski down the mountain ?

Solution :

We draw a rough image of the question for easier understanding.

Refer the attached figure below.

According to question,

Let AB be the height of mountain i.e. AB=1200 feet

The angle of depression is 21 i.e. \theta=21^\circ

We have to find how far does  John ski down the mountain i.e. AC = ?

Using trigonometric,

\cos\theta = \frac{AB}{AC}

\cos(21)= \frac{1200}{AC}

AC=\frac{1200}{\cos(21)}

AC=1285.37

Therefore, John ski down the mountain is 1285.37 feet.

7 0
4 years ago
A rectangular swimming pool measures 14 feet by 30 feet. The pool is
Zolol [24]

Answer:

The total cost of resurface the path is \$600

Step-by-step explanation:

step 1

Find the area of the path

The area of the path is equal to the area of the path plus the swimming pool minus the area of the swimming pool

A=(14+3+3)(30+3+3)-(14)(30)

A=(20)(36)-(14)(30)

A=300\ ft^{2}

step 2

Find the cost of resurface the path

Multiply the area of the path by $2 per square foot

300*2=\$600

4 0
3 years ago
Find the slope of each line.<br> 1) y=− x−5<br> 2) y=− x−1
poizon [28]

1) slope = -1

2) slope = -1

5 0
4 years ago
Order the following numbers from least to greatest.
Simora [160]

Answer:

-53, -24, 0, 18

Step-by-step explanation:

Hope this helps :)

5 0
3 years ago
Read 2 more answers
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0
3 years ago
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