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SOVA2 [1]
3 years ago
8

He lays the shorter edfe and finds the frame

Mathematics
1 answer:
il63 [147K]3 years ago
5 0
By laying on the short edge the frame of it is 6
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Can someone help with this?
valina [46]

Answer:

(a) is 8 x 7 x 3 = 168

(b) is 8 x 7 = 56

(b2) is weird I don't know what it's asking

7 0
2 years ago
Someone please help. I don’t understand these
WITCHER [35]

Answer: very too bad for you buddy study nexts time



Step-by-step explanation:


3 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
Read 2 more answers
Been waiting for half an hour pls help me
Stella [2.4K]

Answer:

13.7 cm

Step-by-step explanation:

  1. there are 360° in a circle and in this image, we can see 90°+90°+66.4°=260.4
  2. since we know that 360°-260.4°=99.6°
  3. The angle measure of arc AD is 99.6°

Now that we covered that, we can use the arc length formula in order to find the length of arc AD.

  1. arc length = 2πr(Θ/360°)
  2. 2π(7.9)(99.6°/360°) = 13.7329
  3. rounded to the nearest tenth = 13.7
3 0
3 years ago
Need help on this<br><br> Z+4&gt;2z
snow_lady [41]

Answer: z < 4

z+4 > 2z

z+4-z > 2z-z ..... Subtract z from both sides

4 > z

z < 4

So the solution set for z is any number that is less than 4, which could be something like z = 2 or z = 3.

7 0
2 years ago
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