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3 years ago

Solve for k. 212 = -4k

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

7 0

Answer:

K = - 53

Step-by-step explanation:

olga2289 [7]3 years ago

3 0

Answer:

k = -53

Step-by-step explanation:

You might be interested in

What’s the least common multiple of 12 and 2

NNADVOKAT [17]

For example, for LCM (12,30) we find:

Using the set of prime numbers from each set with the highest exponent value we take 22 * 31 * 51 = 60. Therefore LCM (12,30) = 60.

7 0

2 years ago

Needs to be in fraction form and simplified <br><br> 3 4/5 + 4 5/6 =? <br><br> 10 points

LenaWriter [7]

Answer:

259/30 or 8 19/30 depending on what format your teacher wants the answer

Step-by-step explanation:

First we can turn both mixed fractions into improper fractions and to do that we multiply the whole number by the denominator and that add that to the top number. So for 3 4/5 we would multiply 3 and 5 and than add 4 getting us to 19/5 doing the same to 4 5/6 gets us to 29/6. Now in order to add fractions we need to get a common denominator. The least common multiple of 5 and 6 is 30 so we will multiply each fraction by whatever number will give us 30 in the denomiator. for 19/5 that number is 6 so our new fraction is 114/30 and for 29/6 that number is 5 so our new number is 145/30. Now we just add the numerators and simplify. 114/30+145/30=259/30

I hope this helps and please don't hesitate to ask if there is anything still unclear!

6 0

2 years ago

No files please........

FinnZ [79.3K]

√7(-8√10+√14)

-8√70+√98

-8√70+√49.2

-8√70+7√2

Just comment if you want to ask

3 0

3 years ago

Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:

ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)

P(E) = $\frac{12}{36} =\frac{1}{3}$

b)P(F)

Favourable events for F = (1,1) (2,2)...(6,6)

P(F) = $\frac{6}{36} =\frac{1}{6}$

c) P(EF)

There is no common element between E and F

P(EF) =0

4 0

3 years ago

Read 2 more answers

Help I need this quick

luda_lava [24]

Area of the 2 end triangles plus area of the 2 rectangular sides plus the area of the bottom rectangle

2 end Triangles
=2x(1/2bh)
=2x1/2x4x6
=24

2 side rectangles
=2(lw)
=2x5x13
=130

Bottom rectangle
=6x13
=78

Total = 24 + 130 + 78 =232

6 0

2 years ago