1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goblinko [34]
3 years ago
6

Which statement is true about this argument?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
6 0

Answer:

The argument is valid by the law of detachment.

Step-by-step explanation:

We first verify that the first statement, "if p, then q" is correct.  If a parallelogram has a right angle, this means that the angle opposite that angle must also be right; this is because the opposite angles of a parallelogram are congruent.

This also means that the adjacent angle to this right angle must also be right; this is because the adjacent angles in a parallelogram are supplementary.

Thus "if p, then q" is true.

The law of detachment states that if I have two statements, one of the form "if p, then q" and the other "p", then the conclusion, "q," is valid.

gayaneshka [121]3 years ago
3 0

The argument is valid by the law of detachment.

You might be interested in
Perpendicular to y = 2x – 6<br> and passing through (4,3)
ladessa [460]

Answer:

y = - 1/2x + 5

Step-by-step explanation:

y = 2x – 6        slope = 2

Perpendicular line slope = -1/2

for (4 , 3)      y = mx + b       y = 3, x = 4,   m = -1/2

b = y - mx = 3 - (-1/2) x 4 = 5

equation: y = - 1/2x + 5

5 0
2 years ago
PLEASE PROVIDE REASONING AND SHOW WORK TO
rjkz [21]

Answer:

A, b, e, f

................

4 0
2 years ago
4/9×5/8×9/25 I want to the answer for this question
wel

Answer:

0.1 ....................

3 0
3 years ago
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
2 years ago
Find the slope of the line whose equation is 15 + 3x = 2y.
Korvikt [17]
15+3x=2y
2y=3x+15
y=\frac{3}{2} x+ \frac{15}{2}
Gradient, m= \frac{3}{2}
6 0
2 years ago
Read 2 more answers
Other questions:
  • (1.5x 109) (3.5 x 109)
    8·2 answers
  • Evaluate f(x) = -2x - 5 for x = 3.<br> A. 11<br> B. -6<br> C. -11<br> D. 1
    13·2 answers
  • Lines that are perpendicular have ___________________ slopes.<br>A. opposite reciprocal<br>b. same
    13·1 answer
  • Need help with this question asap
    5·1 answer
  • 15 points
    12·2 answers
  • While shopping, Dawn finds a backpack that she likes on the sale rack. Its original price is $60,
    7·1 answer
  • Create an arithmetic sequence with a common difference of -10
    6·1 answer
  • Please help I will mark brainliest thanks​
    7·2 answers
  • Step 1: Subtract 3 from both sides of the inequality.
    5·2 answers
  • They are similar or not similar and why?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!