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3 years ago

12

The diagonals of a rectangle measures 18.2 inches. the width of the rectangle is 6.7 is 6.7 inches. find the length of the recta

ngle.

1 answer:

trasher [3.6K]3 years ago

8 0

The length of the rectangle is 16.9

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-2(bx - 5) = 16<br><br> What’s does b and x equal?

horrorfan [7]

To solve this problem you must apply the proccedure shown below:
You have the following equation given in the problem above:
<span>-2(bx - 5) = 16
</span> When you solve for bx, you have:
<span>-2(bx - 5) = 16
-2bx-10=16
-2bx=26
bx=26/-2
bx=-13

When you solve for b, you obtain:
</span><span>-2(bx - 5) = 16
-2bx=26
b=-(26/2x)

When yoo solve for x:
</span>2bx=26
x=-(26/2b)<span>

</span>

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2 years ago

What is the volume of a pentagonal prism that has a base area of 5.16 cm2 and a height of 9 cm?

strojnjashka [21]

The volume of a pentagonal prism that has a base area of 5.16 cm^2 and a height of 9cm is 46.44cm^3

Have fun!

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2 years ago

Read 2 more answers

Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y

sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is $z = 7 \sin (v)$ and the interval for u is $0\le u\le 1$ .

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder $y^2+z^2 = 49$ , that lies between the places x = 0 and x = 1.

$x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?$

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

$0\le u\le 1$

Equation for z.

Replacing the given equation for the parameterization $y = 7 \cos(v)$ on the given equation for the cylinder give us

$(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49$

Solving for z, by moving $49 \cos^2 (v)$ to the other side

$z^2 = 49-49 \cos^2 (v)$

Factoring

$z^2 = 49(1- \cos^2 (v))$

So then we can apply Pythagorean Theorem:

$\sin^2(v)+\cos^2(v) =1$

And solving for sine from the theorem.

$\sin^2(v) = 1-\cos^2(v)$

Thus replacing on the exercise we get

$z^2 = 49\sin^2 (v)$

So we can take the square root of both sides and we get

$z = 7 \sin (v)$

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2 years ago

What is 3/16 in decimal form

lions [1.4K]

The answer for 3/16 in decimal is 0.1875

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