<u>Answer</u>
37.96875
<u>Explanation</u>
In geometric sequence we use the formula below to find the nth of a sequence.
Tn = ar⁽ⁿ⁻¹⁾
Where a ⇒ first term
n ⇒ the term we are looking for
T₆ = 5 × (3/2)⁶⁻¹
= 5 × (3/2)⁵
= 5 × 243/32
= 1215/32
= 37 31/32
= 37.96875
Answer:
S(-2,12)
y= -2(x+2)²+12
Location of coordinate axes:
y=0 → x= -2±√6 (-2-√6,0) (-2+√6,0)
x=0 → y=4 (0,4)
1/5×m+2/3-2=m-2/5
Multiply both sides by 15:
3m+10-30=15m-6
12m=14
m=14/12
m=1.16
The largest number that 8c could be is -15
-16w-26+9w=-61
-16w+9w=-61+26
-7w=-35
w=5
