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2 years ago

13

There are three highways in the county. The number of daily accidents that occur on these highways are Poisson random variables

with respective parameters 0.3, 0.5, and 0.7.
Required:
Find the expected number of accidents that will happen on any of these highways today.

1 answer:

Rashid [163]2 years ago

4 0

Answer:

50% Chance

Step-by-step explanation:

So Pr(0.3, 0.5, and 0.7) = (30% + 50% + 70%) / 300

= 1/2

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Please help me out with this

Ivanshal [37]

Answer:

374.1

Step-by-step explanation:

Area of Hexagon = $\frac{3\sqrt{3} }{2} * a^{2}$

The ' a ' is the side length.

So now we just plug in the values

$\frac{3\sqrt{3} }{2} *12^{2}$ = 374.12

3 0

2 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

1 year ago

Solve each system of equations algebraically y= x-6 y= 2x

lbvjy [14]

Answer: x = -6

Step-by-step explanation: The problem gave us the y value, so we can just substitute it into the equation and solve it.

y = x - 6

y = 2x

2x = x - 6 (substitute the y value into the equation)

1x = -6 (subtract x on each side)

x = -6 (1x is basically saying x so you do not need to divide)

3 0

3 years ago

A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m

agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

$x+20\%x=18$

$x(1+0.20)=18$ (∴20%= $\frac{20}{100}$ =0.20)

$x(1.20)=18$

$x=\frac{18}{1.20}$

$x=15$

Hence, the usual size of the container is 15 ounces.

3 0

3 years ago

Number 2 rewrite as a single power

Paul [167]

Answer:

-625

Step-by-step explanation:

I think so..

4 0

3 years ago