An even function can be reflected about the y axis and map onto itself
example: y=x^2
an odd function can be reflected about the origin and map onto itself
example: y=x^3
a simple test is the following
if f(x) is even then f(-x)=f(x)
if f(x) is odd then f(-x)=-f(x)
so
even function
subsitute -x for each and see if we get the same function
remember to fully expand these
g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original one
g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
not same because the original has -2x
not even
g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
same, it's even
g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
not the same, not even
g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
not same, not even
g(x)=2x²+1 is the even function
Well the slope formula is y² - y¹ / x² - x¹.
If there was a picture I could help!
Answer:
No more than ≥
Not under ≤
No less than ≤
maximum ≥
Greater than or equal to ≥
Less than or equal to ≤
Does not exceed ≥
At most ≥
At least ≤
Minimum ≤
Answer: it will take 5 people 6.4 hours to do the work.
Step-by-step explanation:
The number of hours required to do a job varies inversely as the number of people working. Let h represent the number of hours required to do the job. Let p represent the number of people working. Therefore,
h is inversely proportional to p
Introducing a constant of variation, k, it means that
h = k/p
It takes 8 hours for 4 people to paint the inside of a house. Therefore
8 = k/4
k = 8×4 = 32
The formula becomes
h = 32/p
To determine how many hours it will take 5 people to do the work, we will substitute p = 5 into the formula. It becomes
h = 32/5 = 6.4 hours
Answer:
Consider f: N → N defined by f(0)=0 and f(n)=n-1 for all n>0.
Step-by-step explanation:
First we will prove that f is surjective. Let y∈N be any natural number. Define x as the number x=y+1. Then x∈N, and f(x)=x-1=(y+1)-1=y. We conclude that f is surjective.
However, f is not injective. Take x1=0 and x2=1. Then x1≠x2 but f(x1)=0 and f(x2)=x2-1=1-1=0. We have shown that there are two natural numbers x1,x2 such that x1≠x2 but f(x1)=f(x2), that is, f is not injective.
Note:
If 0∉N in your definition of natural numbers, the same reasoning works with the function f: N → N defined by f(1)=1 and f(n)=n-1 for all n>1. The only difference is that you consider x1=1, x2=2 for the injectivity.
