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Sav [38]
3 years ago
10

In a large population of adults, the mean IQ is 112 with a standard deviation of 20. Suppose 200 adults are randomly selected fo

r a market research campaign. The distribution of the sample mean IQ is (a)exactly Normal, mean 112, standard deviation 20. (b)approximately Normal, mean 112, standard deviation 0.1. (c)approximately Normal, mean 112, standard deviation 1.414. (d)approximately Normal, mean 112, standard deviation 20. (e)exactly Normal, mean 112, standard deviation 1.414.
Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

(c)approximately Normal, mean 112, standard deviation 1.414.

Step-by-step explanation:

To solve this problem, we have to understand the Central Limit Theorem

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 112, \sigma = 20, n = 200

Using the Central Limit Theorem

The distribution of the sample mean IQ is approximately Normal.

With mean 112

With standard deviation s = \frac{20}{\sqrt{200}} = 1.414

So the correct answer is:

(c)approximately Normal, mean 112, standard deviation 1.414.

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Distributive property of multiplication 98 times 7
horsena [70]

Answer:

686

Step-by-step explanation:

6 0
3 years ago
I don’t know what to do, please help!!
Rainbow [258]

Answer:

b 7

Step-by-step explanation:

open the bracket and the power gets cancelled because it will be 5/5

then answer will be 7 to the power 1 which is equals to 7

7 0
3 years ago
How do i do this pls help me
Delvig [45]

Answer:

y =  \frac{1}{7} x + 7

Step-by-step explanation:

x-7y = -49

i) move x to the right-hand side and change its sign

-7y = -49-x

ii) change the signs on both sides of the equation

7y = 49+x

iii) divide both sides of the equation by 7

\frac{7y}{7}  = \frac{49}{7}  +  \frac{x}{7}

y = 7 +  \frac{1}{7}  x

iv) use the commutative property to reorder the terms

* commutative property: a+b = b+a

y =  \frac{1}{7} x + 7

3 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
This is what I got,
USPshnik [31]
1/x + 1/y = 8
x + y = 8
6/x + 12/y = 72n
4 0
4 years ago
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