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4 years ago

What is the greatest common factor of: 6c^3d - 12c^2d^2 + 3cd?

Mathematics

1 answer:

VMariaS [17]4 years ago

4 0

I hope this helps you

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B) Write down the formula to find the perimeter of a circle.

rewona [7]

Answer:

C = 2πr

Step-by-step explanation:

We know that, the perimeter of a figure is equal to the sum of all sides.

A circle having no sides.

The perimeter of a circle = The circumference of the circle

The formula for the circumference of the circle is given by :

C = 2πr

Where

r is the radius of the circle

Hence, this is the required solution.

7 0

3 years ago

If the denominator of a fraction is multiplied by 2,the value of the fraction is

kow [346]

Answer:

Half of its original

Step-by-step explanation:

When multiplying a denominator by a whole number, he value decreases accordingly, in other word, it changes inversely.

Examples:

In 1/2, if 2 is multiplied by 2, the value becomes 1/4, which is half of 1/2

In 1/4, if 4 is multiplied by 2, the value becomes 1/8 which is half of 1/4.

Hope this helps

Good luck

8 0

4 years ago

Prove that tan2A is equal to 2tanA/1-tan^2A

Neko [114]

$\tan(2\alpha)=\dfrac{2\tan \alpha }{1-\tan^2 \alpha}\\\\\\\dfrac{\sin(2\alpha)}{\cos(2\alpha)}=\dfrac{\dfrac{2\sin\alpha}{\cos\alpha}}{1-\dfrac{\sin ^2\alpha}{\cos^2\alpha}}\\\\\\\dfrac{\sin(2\alpha)}{\cos(2\alpha)}=\dfrac{\dfrac{2\sin\alpha}{\cos\alpha} }{\dfrac{\cos^2\alpha}{\cos^2\alpha}-\dfrac{\sin ^2\alpha}{\cos^2\alpha}}\\\\\\\dfrac{\sin(2\alpha)}{\cos(2\alpha)}=\dfrac{\dfrac{2\sin\alpha}{\cos\alpha} }{\dfrac{\cos^2\alpha-\sin^2 \alpha}{\cos^2\alpha}}$

$\dfrac{\sin(2\alpha)}{\cos(2\alpha)}=\dfrac{2\sin\alpha}{\cos\alpha} \cdot\dfrac{\cos^2\alpha}{\cos^2\alpha-\sin^2 \alpha}\\\\\\\dfrac{\sin(2\alpha)}{\cos(2\alpha)}=\dfrac{2\sin\alpha\cos\alpha}{\cos^2\alpha-\sin^2 \alpha} \\\\\\\dfrac{\sin(2\alpha)}{\cos(2\alpha)}=\dfrac{\sin(2\alpha)}{\cos(2\alpha)}$

8 0

3 years ago

Read 2 more answers

-10=2x-4x how do you simplify this

ozzi

The given formula is,

$-10=2x-4x$

Now solving for x,

$\begin{gathered} -10=-2x \\ x=\frac{-10}{-2}=5 \end{gathered}$

5 0

1 year ago

Help binomial distributions

Ymorist [56]

We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is

$P(\text{k successed on n trials}) = \binom{n}{k}p^k(1-p)^{n-k}$

Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.

We can compute their probability and sum them: $\binom{5}{3}\left(\frac{3}{7}\right)^3\left(\frac{4}{7}\right)^2 + \binom{5}{4}\left(\frac{3}{7}\right)^4\left(\frac{4}{7}\right)^1 + \binom{5}{5}\left(\frac{3}{7}\right)^5 \approx 0.36788$

So, the answer is about 36.79%

3 0

3 years ago