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Zolol [24]
2 years ago
6

Ms jenkins has a grass lawn that is 24m wide and 30m long. mr jenkins cuts the grass at a reate of 9m per minute. how long will

it take mr jenkins to cut all the grass?
Mathematics
1 answer:
Kisachek [45]2 years ago
5 0

It will take Mr. Jenkins 1 hr and 20 minutes to cut all the grass.

To know how long it will take Mr. Jenkins to cut all the grass, get the total area of the lawn and divide it by the rate Mr. Jenkins cut the grass.

The area of the lawn can be calculated using the formula for the area of a rectangle given by:

A = l x w

where l is the length and w is the width.

Using this formula, the grass lawn that is 24 m wide and 30 m long has an area of:

A = l x w

where

l = 30 m

w = 24 m

A = 30 m x 24 m

A = 720 m^2

Meanwhile, the time it will take Mr. Jenkins to cut the grass lawn with an area of 720 m^2 can be computed using the rate.

amount = rate x time

720 m^2 = 9 m^2/minute x t

t = 720 / 9

t = 80 minutes = 1 hr 20 minutes

To know more about rate, visit brainly.com/question/24950565.

#SPJ4

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The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an
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The length of the side of an equilateral traingle s=2\sqrt{2} inches

Step-by-step explanation:

Given that the area of an equilateral triangle is given by

A=3^\frac{1}{2}s^2

It can be written as

a=\frac{\sqrt{3}}{4} s^2 Square inches        (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is 12^\frac{1}{2} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches

It can be written as

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Now comparing equations (1) and (2) we get

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\frac{\sqrt{3}}{4}s^2=\sqrt{4\times 3}

Dividing by \frac{\sqrt{3}}{4} on both sides we get

\frac{\frac{\sqrt{3}}{4}s^2}{\frac{\sqrt{3}}{4}}=\frac{2\sqrt{3}}{\frac{\sqrt{3}}{4}}

\frac{\sqrt{3}}{4}s^2\times\frac{4}{\sqrt{3}}=2\sqrt{3}\times\frac{4}{\sqrt{3}}

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Therefore s=2\sqrt{2} inches

Therefore the length of the side of an equilateral traingle s=2\sqrt{2} inches

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