Can y'all help on 39 and 40 and plz explain

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

5 0

I only know 40
there are 7 spaces and there are 4 odd and three even spaces.
it is asking what is the probably of not landing on an odd.
there are 4 odds and the rest are even.
so the it is 3 spaces out of 7

it is J 3 over 7

Degger [83]3 years ago

4 0

I am not sure the answer for 39 but #40 is J

The question is asking you what fraction of the spinner show the arrow that will NOT land of odd #s. the circle is cut into 7, there is only 3 #s that are not odd. 7 is the denominator and 3 is the numerator

I am sorry that my explaination might confuse you
Hope this help:) :P

You might be interested in

What is the area of the polygon?

Elenna [48]

Hello,

Answer C
13*(12-3)+3*10=147

6 0

3 years ago

Find a third-degree polynomial equation with rational coefficients that has roots –4 and 2 + i

ella [17]

If it has rational coefients and is a polygon
if a+bi is a root then a-bi is also a root

the roots are -4 and 2+i
so then 2-i must also be a root

if the rots of a poly are r1 and r2 then the factors are
f(x)=(x-r1)(x-r2)

roots are -4 and 2+i and 2-i

f(x)=(x-(-4))(x-(2+i))(x-(2-i))
f(x)=(x+4)(x-2-i)(x-2+i)
expand
f(x)=x³-11x+20

8 0

3 years ago

A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th

mestny [16]

Let $x$ be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

$400\cdot 40\cdot x = 16000x$

After 10 days, the 400 men will have consumed

$400\cdot 10\cdot x = 4000x$

food, impliying that the food remaining is

$16000x-4000x=12000x$

If 200 more men join the garrison, there are now 600 men. Each of them requires $x$ food each day, and there are $12000x$ units of food remaining. They will last