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3 years ago

Which products result in a difference of squares or a perfect square trinomial? Check all that apply.

Mathematics

2 answers:

SVEN [57.7K]3 years ago

3 0

The following are the answers for these:

(5x + 3)(5x – 3) ----> Difference of squares

(7x + 4)(7x + 4) ----> Perfect square trinomial

(2x + 1)(x + 2) ----> Neither

(4x – 6)(x + 8) ----> Neither

(x – 9)(x – 9)-----> Perfect square trinomial

(–3x – 6)(–3x + 6) -----> Difference of squares.

The easiest way to tell these is that if the parenthesis are exactly the same it will be a perfect square trinomial. If the parenthesis are the same except for the sign in between the terms, it is a difference of square. If it has neither of these, then it is neither.

kvv77 [185]3 years ago

3 0

Answer:

Your answers are:

Step-by-step explanation:

A) (5x + 3)(5x – 3)

B) (7x + 4)(7x + 4)

E) (x – 9)(x – 9)

F) (–3x – 6)(–3x + 6)

I just did the assignment, and I got a 100%. I swear, this is right!

I hope this helps!

- sincerelynini

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2 years ago

Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?

oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations

(x-1)(x+3)=17+x ..... (1) and

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).

Therefore, there will be the same solution set for equations (1) and (2). (Answer)

There are two equations

(x-1)(x+3)=17+x ..... (3) and

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

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3 years ago

Read 2 more answers

2.5% of a population are infected with a certain disease. There is a test for the disease, however the test is not completely ac

Aleks04 [339]

Answer:

$P(disease/positivetest) = 0.36116$

Step-by-step explanation:

This is a conditional probability exercise.

Let's name the events :

I : ''A person is infected''

NI : ''A person is not infected''

PT : ''The test is positive''

NT : ''The test is negative''

The conditional probability equation is :

Given two events A and B :

P(A/B) = P(A ∩ B) / P(B)

$P(B) >0$

P(A/B) is the probability of the event A given that the event B happened

P(A ∩ B) is the probability of the event (A ∩ B)

(A ∩ B) is the event where A and B happened at the same time

In the exercise :

$P(I)=0.025$

$P(NI)= 1-P(I)=1-0.025=0.975\\P(NI)=0.975$

$P(PT/I)=0.904\\P(PT/NI)=0.041$

We are looking for P(I/PT) :

P(I/PT)=P(I∩ PT)/ P(PT)

$P(PT/I)=0.904$

P(PT/I)=P(PT∩ I)/P(I)

0.904=P(PT∩ I)/0.025

P(PT∩ I)=0.904 x 0.025

P(PT∩ I) = 0.0226

P(PT/NI)=0.041

P(PT/NI)=P(PT∩ NI)/P(NI)

0.041=P(PT∩ NI)/0.975

P(PT∩ NI) = 0.041 x 0.975

P(PT∩ NI) = 0.039975

P(PT) = P(PT∩ I)+P(PT∩ NI)

P(PT)= 0.0226 + 0.039975

P(PT) = 0.062575

P(I/PT) = P(PT∩I)/P(PT)

$P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116$

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Answer:

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Step-by-step explanation:

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