Answer:
-7
Step-by-step explanation:
Because there is no multiplication, it is just the x^2 terms. There is a -(-2x^2) and a -9x^2, so it is 2x^2 and -9x^2 or -7x^2, so the coefficient is -7.
Since a right triangle has special rules to it such that the hypotenuse squared equals the sum of the squares of the other 2 sides. In other words, if the hypotenuse = c, and the 2 smaller sides are a and b, then:
![{c}^{2} = {a}^{2} + {b}^{2}](https://tex.z-dn.net/?f=%20%7Bc%7D%5E%7B2%7D%20%20%3D%20%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20)
Solving for c (hypotenuse), we get:
![\sqrt{({c}^{2})} = \sqrt{({a}^{2}+{b}^{2} )} \\ c = \sqrt{({a}^{2}+{b}^{2} )}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28%7Bc%7D%5E%7B2%7D%29%7D%20%3D%20%20%20%5Csqrt%7B%28%7Ba%7D%5E%7B2%7D%2B%7Bb%7D%5E%7B2%7D%20%29%7D%20%5C%5C%20c%20%3D%20%20%5Csqrt%7B%28%7Ba%7D%5E%7B2%7D%2B%7Bb%7D%5E%7B2%7D%20%29%7D%20)
Therefore c is the root of the square of the other sides. So by having root18, it's like saying:
![\sqrt{18} = \sqrt{({a}^{2} + {b}^{2} )} \\ 18 = {a}^{2} + {b}^{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B18%7D%20%3D%20%20%5Csqrt%7B%28%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%29%7D%20%20%5C%5C%2018%20%3D%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%20)
Getting rid of the square root, so sides a and b must have their squares total 18:
the only squares < 18 are: 16 (4×4), 9 (3×3), 4 (2×2), and 1 (1×1)
of those above added in any order of two of them, only 16+4
![18 = 17 + 1 - - > \sqrt{17} \: and \: 1 \\ 18 = 16 + 2 - - > \sqrt{16} \: and \: \sqrt{2} \\ ... \: 4 \: and \: \sqrt{2} \\ 18 = 15 + 3 - - > \sqrt{15} \: and \: \sqrt{3}](https://tex.z-dn.net/?f=18%20%3D%2017%20%2B%201%20-%20%20-%20%20%3E%20%20%5Csqrt%7B17%7D%20%20%5C%3A%20and%20%5C%3A%201%20%5C%5C%2018%20%3D%2016%20%2B%202%20-%20%20-%20%20%3E%20%20%5Csqrt%7B16%7D%20%5C%3A%20and%20%5C%3A%20%20%5Csqrt%7B2%7D%20%20%5C%5C%20...%20%5C%3A%204%20%5C%3A%20and%20%5C%3A%20%20%5Csqrt%7B2%7D%20%20%5C%5C%2018%20%3D%2015%20%2B%203%20-%20%20-%20%20%3E%20%20%5Csqrt%7B15%7D%20%5C%3A%20%20and%20%5C%3A%20%20%5Csqrt%7B3%7D%20)
![18 = 14 + 4 - - > \sqrt{14} \: and \: \sqrt{4} \\ ... \sqrt{14} \: and \: 2 \\ 18 = 13 + 5 - - > \sqrt{13} \: and \: \sqrt{5} \\ 18 = 12+ 6 - - > \sqrt{12} \: and \: \sqrt{6}](https://tex.z-dn.net/?f=18%20%3D%2014%20%2B%204%20-%20%20-%20%20%3E%20%20%5Csqrt%7B14%7D%20%5C%3A%20%20and%20%5C%3A%20%20%5Csqrt%7B4%7D%20%20%5C%5C%20...%20%5Csqrt%7B14%7D%20%5C%3A%20and%20%5C%3A%202%20%20%5C%5C%2018%20%3D%2013%20%2B%205%20-%20%20-%20%20%3E%20%20%5Csqrt%7B13%7D%20%5C%3A%20and%20%5C%3A%20%20%5Csqrt%7B5%7D%20%20%20%5C%5C%2018%20%3D%2012%2B%206%20-%20%20-%20%20%3E%20%20%5Csqrt%7B12%7D%20%5C%3A%20%20and%20%5C%3A%20%20%5Csqrt%7B6%7D%20)
![18 = 11 + 7 - - > \sqrt{11} \: and \: \sqrt{7} \\ 18 = 10 + 8 - - > \sqrt{10} \: and \: \sqrt{8} \\ ... \sqrt{10} \: and \: 2 \sqrt{2} \\ 18 = 9 + 9 - - > \sqrt{9} = 3 \: and \: 3](https://tex.z-dn.net/?f=18%20%3D%2011%20%2B%207%20-%20%20-%20%20%3E%20%20%5Csqrt%7B11%7D%20%5C%3A%20%20and%20%5C%3A%20%20%5Csqrt%7B7%7D%20%20%5C%5C%2018%20%3D%2010%20%2B%208%20-%20%20-%20%20%3E%20%20%5Csqrt%7B10%7D%20%5C%3A%20%20and%20%5C%3A%20%20%5Csqrt%7B8%7D%20%20%5C%5C%20...%20%5Csqrt%7B10%7D%20%5C%3A%20%20and%20%5C%3A%202%20%5Csqrt%7B2%7D%20%20%5C%5C%2018%20%3D%209%20%2B%209%20-%20%20-%20%20%3E%20%20%5Csqrt%7B9%7D%20%20%3D%203%20%5C%3A%20and%20%5C%3A%203%20)
I HOPE THAT IS ALONG THE LINE THAT WAS ASKED FOR!!! :-D
I assume you mean -5 and 3/4 instead of -53/4. In that case, it cannot be A, as -5.8 is less than -5.75 (AKA -5 3/4). It cannot be C or D either, though, as the number has to be less than -5.5, and -5.4 or -5.3 are both more than -5.5. Thus, by process of elimination, it has to be B, - 5.7. Hope I helped! Good luck in future!
Answer:
3) 11x+3
4) 8x³+2x²+2x+8
Step-by-step explanation:
Answer:
49. to the left two spaces (place values)
50. 4.35 m
51. to the right three spaces (place values)
52. 12,000 mL
53. to the right six spaces (place values)
54. 3,000,000
Step-by-step explanation:
49. 1 centimeter is equal to
of a meter. In other words, there are 100 cm in 1 meter. To convert from cm to m, you would move the decimal to the left because meters are larger than centimeters meaning a large number of centimeters would convert to a smaller number of meters. The decimal will move two places because there are 100 cm in 1 meter. (look at the number of zeros to determine how many spaces to move)
50. Follow the rule from the 49:
435.00 → 4.35
51. 1 liter is equal to 1000 milliliters. This means the number will increase, moving the decimal to the right. The decimal will move three places because each place value equals 10x and 10 · 10 · 10 = 1000. (look at the number of zeros to determine how many spaces to move)
52. Follow the rule from 51:
12.00 → 12,000
53. 1 megameter is equal to 1,000,000 meters. This means the number will increase, moving the decimal to the right. The decimal will move six spaces because each place value equals 10x. 10 · 10 · 10 · 10 · 10 · 10 = 1,000,000 (look at the zeros to determine how many spaces to move)
54. Follow the rule from 53:
3.00 → 3,000,000