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Sati [7]
3 years ago
13

Which expression is equivalent to (x4)^9

Mathematics
1 answer:
meriva3 years ago
8 0

Answer:

Step-by-step explanation:

(a^{m})^{n}=a^{m*n}\\\\(x^{4})^{9}=x^{4*9}=x^{36}

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Jeffrey is going to charge an initial fee of $10 for mowing lawns, plus an hourly rate. He knows that he wants to
zmey [24]

Answer:

B 15

Step-by-step explanation:

10 dollar + 2 hours of work 15 x 2

4 0
3 years ago
Does anyone know how to Graph f(x)=51(2)^x
3241004551 [841]
This is an exponential function.   

If x = 0, 2^x = 2^0 = 1.  The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.

Make a table and graph the points:

x        y=51*2^x                                point (x,y)
--       ---------------                            ---------------
0             51                                       (0,51)
2            51*2^2 = 51(4) = 204           (2,204)             and so on.

The graph shows up in both Quadrants I and II.  Its y-intercept is (0,51).  Its slope is always positive.

5 0
3 years ago
Read 2 more answers
Evaluate 3 + (a + 4)(8 - b) when a = 5 and b = 6.<br> The value of the expression is
levacccp [35]

Answer:

21

Step-by-step explanation:

you plug in 5 for a and 6 for b and solve.

8 0
3 years ago
Read 2 more answers
Convert to decimal expression 0.2777... To a fraction
AlladinOne [14]
Formula is

d = d(10^k+p - 10^k) / 10^k+p - 10^k

where d = the decimal;
k = number of the non repeating decimal digits; which in this case is one
p = repeating decimal digits which in this case is one


Final Answer for this question after simplifying is 5/18
5 0
3 years ago
Michelle's father deposited $1,000 into a savings account when she was born. The annual interest rate is
prohojiy [21]

Answer:

Michelle's age = 16

Step-by-step explanation:

As we know,

Amount = P (1 + r)^{t} where

P = Principal amount

r = rate of interest

t = time

Given ,

P = $1000

r = 4.5 % = \frac{4.5}{100} = 0.045

Now,

Given that Amount reaches more than $2000

⇒P (1 + r)^{t}  > 2000

⇒1000(1 + 0.045)^{t} > 2000

⇒(1.045)^{t} > 2

Now,

we put the value of t from 0 , 1, 2, ..... untill the above equation does not satisfy

Now,

for t = 0

(1.045)^{0} = 1 \ngeq 2

for t = 1

(1.045)^{1} = 1.045 \ngeq 2

for t = 2

(1.045)^{2} = 1.092 \ngeq 2

for t = 3

(1.045)^{3} = 1.14 \ngeq 2

for t = 4

(1.045)^{4} = 1.19 \ngeq 2

for t = 5

(1.045)^{5} = 1.25 \ngeq 2

for t = 6

(1.045)^{6} = 1.30 \ngeq 2

for t = 7

(1.045)^{7} = 1.36 \ngeq 2

for t = 8

(1.045)^{8} = 1.42 \ngeq 2

for t = 9

(1.045)^{9} = 1.48 \ngeq 2

for t = 10

(1.045)^{10} = 1.55 \ngeq 2

for t = 11

(1.045)^{11} = 1.62 \ngeq 2  

for t = 12

(1.045)^{12} = 1.69 \ngeq 2

for t = 13

(1.045)^{13} = 1.77 \ngeq 2

for t = 14

(1.045)^{14} = 1.85 \ngeq 2  

for t = 15

(1.045)^{15} = 1.93 \ngeq 2

for t = 16

(1.045)^{16} = 2.02 >  2

It satisfies at t= 16

∴ we get

Michelle's age = 16

4 0
3 years ago
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