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Ray Of Light [21]

3 years ago

12

An extreme value of a function in other words

1 answer:

zubka84 [21]3 years ago

7 0

Answer:

Maximum or minimum

Step-by-step explanation:

An extreme value of a function are the highest and lowest points on the function. This is where the y-value is at its highest or lowest values. If a function is continuous and approaches infinity or negative infinity on either end, then its extreme values are local maximums or minimums. These are max and min over a specific part of the function. They are called local since the function continues in one or both directions forever.

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I dont know what to do please help me

ipn [44]

Answer:

A

Step-by-step explanation:

Time Distance

0 0

2 2*25 = 50

4 4*25 = 100

6 6*25= 150

8 8 * 25 = 200

7 0

3 years ago

Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2

Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$ .

The sine difference identity is:

$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

We need to find a way to put some or all of these together to get:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$ .

So I do notice on the right hand side the $\sin(a+b)$ and the $\sin(a-b)$ .

Let's start there then.

There is a plus sign in between them so let's add those together:

$\sin(a+b)+\sin(a-b)$

$=[\sin(a+b)]+[\sin(a-b)]$

$=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]$

There are two pairs of like terms. I will gather them together so you can see it more clearly:

$=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]$

$=2\sin(a)\cos(b)+0$

$=2\sin(a)\cos(b)$

So this implies:

$\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)$

Divide both sides by 2:

$\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)$

By the symmetric property we can write:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$

3 0

3 years ago

How do you write this statement as a equation? 2 more than 3 times a number is 17

evablogger [386]

5 times n=17 because you have to use algebra

5 0

3 years ago

Read 2 more answers

What is the domain of the function below?

Romashka [77]

The domain would be (4, infinity) so most likely your answer would be D.

6 0

3 years ago

Read 2 more answers

13 - (n • 6) = 50<br> Pls help what would be the equation

olya-2409 [2.1K]

Answer:

n=-17/3

Step-by-step explanation:

16-(n.6)=50

16-6n=50

-6n=34

n=34/-6

n=-17/3

5 0

2 years ago