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Ray Of Light [21]
3 years ago
12

An extreme value of a function in other words

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

Maximum or minimum

Step-by-step explanation:

An extreme value of a function are the highest and lowest points on the function. This is where the y-value is at its highest or lowest values. If a function is continuous and approaches infinity or negative infinity on either end, then its extreme values are local maximums or minimums. These are max and min over a specific part of the function. They are called local since the function continues in one or both directions forever.

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I dont know what to do please help me
ipn [44]

Answer:

A

Step-by-step explanation:

Time        Distance

0               0

2               2*25 = 50

4               4*25 = 100

6               6*25= 150

8                 8 * 25 = 200

7 0
3 years ago
Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2
Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b).

The sine difference identity is:

\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a).

The cosine addition identity is:

\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b).

The cosine difference identity is:

\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b).

We need to find a way to put some or all of these together to get:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}.

So I do notice on the right hand side the \sin(a+b) and the \sin(a-b).

Let's start there then.

There is a plus sign in between them so let's add those together:

\sin(a+b)+\sin(a-b)

=[\sin(a+b)]+[\sin(a-b)]

=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]

There are two pairs of like terms. I will gather them together so you can see it more clearly:

=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]

=2\sin(a)\cos(b)+0

=2\sin(a)\cos(b)

So this implies:

\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)

Divide both sides by 2:

\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)

By the symmetric property we can write:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}

3 0
3 years ago
How do you write this statement as a equation? 2 more than 3 times a number is 17
evablogger [386]
5 times n=17 because you have to use algebra
5 0
3 years ago
Read 2 more answers
What is the domain of the function below?
Romashka [77]
The domain would be (4, infinity) so most likely your answer would be D.
6 0
3 years ago
Read 2 more answers
13 - (n • 6) = 50<br> Pls help what would be the equation
olya-2409 [2.1K]

Answer:

n=-17/3

Step-by-step explanation:

16-(n.6)=50

16-6n=50

-6n=34

n=34/-6

n=-17/3

5 0
2 years ago
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