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2 years ago

Two mixed numbers with the sum of three

Mathematics

2 answers:

kifflom [539]2 years ago

5 0

1 3/4 + 1 1/4 = 3
hope that helps

Alexxx [7]2 years ago

4 0

1 1/2+1 1/2 because 1 1/2 is = to 1.50 and 1.50+1.50=3.00

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7x2 - 5x+3<br> + 2x2 + 7x-8

daser333 [38]

Answer:G

Step-by-step explanation:

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3 years ago

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The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,

Mama L [17]

Answer:

$(a)\ P(x = 0) = 0.2725$

$(b)\ P(x \ge 1) =0.7275$

$(c)\ P(x \le 2) = 0.8948$

Step-by-step explanation:

Given

$n = 8$ --- 8 friends

$p = 15\%$ --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

$P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}$

Solving (a): P(x = 0) --- None has done one time fling

$P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}$

$P(x = 0) = 1* 1 * (1 - 0.15)^{8}$

$P(x = 0) = 0.85^8$

$P(x = 0) = 0.2725$

Solving (b): $P(x \ge 1)$

To do this, we make use of compliment rule:

$P(x = 0) + P(x \ge 1) =1$

Rewrite as:

$P(x \ge 1) =1 - P(x = 0)$

$P(x \ge 1) =1 - 0.2725$

$P(x \ge 1) =0.7275$

Solving (c): $P(x\le 2)$ --- Not more than 2 has one time fling

This is calculated as:

$P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)$

We have:

$P(x = 0) = 0.2725$

$P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}$

$P(x = 1) = 8* (0.15) * (1 - 0.15)^7$

$P(x = 1) = 0.3847$

$P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}$

$P(x = 2) = 28* (0.15)^2 * (1-0.15)^6$

$P(x = 2) = 0.2376$

So:

$P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)$

$P(x \le 2) = 0.2725 + 0.3847 + 0.2376$

$P(x \le 2) = 0.8948$

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2 years ago

-5.23-9.3= what idk what

kkurt [141]

Answer:

-14.53

Step-by-step explanation:

-5.23-9.3=-14.53 it's a negative plus a negative

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2 years ago

There are 305 days in a year how many days in 3 years

erastovalidia [21]

Answer:

Step-by-step explanation:

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2 years ago

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John and Beth plan to visit a bookstore. Based on their previous visits to this bookstore, the probability distributions for the

lora16 [44]

Answer:

D) 0.1250

Step-by-step explanation:

Let P(J) = Probability of John to purchase 0 books

Let P(B) = Probability of Beth to purchase 0 books

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Since the decisions to purchase books are two independents events,

P(J∩B) = P(J) * P(B)

P(J) = 0.5

P(B) = 0.25

P(J∩B) = 0.5 * 0.25

P(J∩B) = 0.125

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2 years ago