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asambeis [7]
3 years ago
6

A dog trainer has 96 ft of fencing that will be used to create a rectangular work area. Encloses area of 320 ft^2. What will be

the dimensions of the area
Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

<em>The dimensions of the area will be 8 ft x 40 ft</em>

Step-by-step explanation:

<u>Area and Perimeter</u>

The perimeter can be understood as the distance measured around a shape. The area gives us the idea of the space occupied by the shape. Being w and l the width and length of a rectangle, the perimeter and areas can be computed as follows

A=wl

P=2w+2l

The dog trainer has 96 ft of fencing to cover a 320 ft^2 rectangular area. This means that

wl=320

2w+2l=96

A system of equations is formed

\left\{\begin{matrix}wl=320\\ 2w+2l=96\end{matrix}\right

We divide the last equation by 2

w+l=48

solve for w

w=48-l

Replacing in the first equation

(48-l)l=320

Operating and arranging

l^2-48l+320=0

(l-8)(l-40)=0

We have two possible answers

l=8,\ l=40

Which gives us

w=40,\ w=8

In any case, the dimensions of the area will be 8 ft x 40 ft

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Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

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