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Alenkinab [10]
3 years ago
13

(8x^3-6x)-(10x^3+3x^2-x)

Mathematics
1 answer:
den301095 [7]3 years ago
7 0
The answer is on the pic

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In a cave, a stalactite gets 44 millimeters longer each year. this year it is 72 centimeters long. how many years until it is 1
iragen [17]

Answer:

6.36 years (the .36 repeats), so rounded is 6.4.

Step-by-step explanation:

First, I'm going to convert all measurements to meters.

Since 1000 mm = 1 m, divide 44 by 1000.

44/1000 = 0.044 m

Since 100 cm = 1 m, divide 72 by 100.

72/100 = 0.72 m

Next, I'm going to setup an equation using y = mx + b.

b is the beginning amount which is 0.72.

m in the equation represents the rate which is 0.044.

y represents the total which is 1.

Plugin the numbers and solve for x.

1 = 0.044x + 0.72

1 - 0.72 = 0.044x + 0.72 - 0.72

0.28 = 0.044x

0.28/0.044 = 0.044x/0.044

6.36 = x

7 0
2 years ago
Write a real world scenario that matches the following equation. 15+3h=30 Then solve for the equation
arsen [322]
Bowling costs 15 dollars per person and 3 is amount of money per game it cost to play. If you play 5 games then you pay a total of 30 dollars. 
7 0
3 years ago
How this concepts are used in different situations?​
andriy [413]

Answer:

Positive thinking is all of mind also positive

Step-by-step explanation:

4 0
3 years ago
Genevieve works on her scrapbook from 11:27 am to 11:58 am. How many minutes does she work on her scrapbook
Mnenie [13.5K]

Answer:

31

Step-by-step explanation:

time is tricky due to the 60 minute interface. In those questions add to the lower number until you hit a rounded number.

Fortunately you don't need to use this in this problem, and can just subtract 58-27 to get 31

5 0
2 years ago
A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. How much time does it take for the r
Bogdan [553]
Check the picture below.

so it hits the ground when y = 0, thus

\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{16}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{5}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}

\bf h(t)=-16t^2+16t+5\implies \stackrel{h(t)}{0}=-16t^2+16t+5
\\\\\\
16t^2-16t-5=0\implies (4t+1)(4t-5)=0\\\\
-------------------------------\\\\
4t+1=0\implies 4t=-1\implies t=-\cfrac{1}{4}\\\\
-------------------------------\\\\
4t-5=0\implies 4t=5\implies t=\cfrac{5}{4}\implies \boxed{t=1\frac{1}{4}}

since "t" is seconds it took, it can't be a negative amount.

5 0
3 years ago
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