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3 years ago

What digits can you insert so that 4 6 rounds to 500

Mathematics

1 answer:

Annette [7]3 years ago

3 0

You can round 46 to 50, not 500

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What value of x makes the equation below true 6x-7=26

VikaD [51]

Answer:

11/2

Step-by-step explanation:

6x−7=26

Step 1: Add 7 to both sides.

6x−7+7=26+7

6x=33

Step 2: Divide both sides by 6.

x= 11/2

6 0

3 years ago

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Describe the transformation from y= x + 4 to y= .5x + 4 Group of answer choices compresses stretches shifts right 4 shifts left

Nina [5.8K]

Answer:

This type of transformation is a horizontal stretch.

Step-by-step explanation:

Given

$y = x + 4$

$y = .5x + 4$

Required

Determine the type of transformation

The first function can be expressed as:

$f(x) = x + 4$

While the second function is:

$g(x) = f(0.5x)$

Solving f(0.5x), we have to substitute 0.5x for x in $f(x) = x + 4$

$f(0.5x) = 0.5x + 4$

So:

The second function is:

$g(x) = 0.5x + 4$

This type of transformation is a horizontal stretch.

i.e. f(x) stretched to g(x)

4 0

3 years ago

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 54 -3. What is the point slope

dangina [55]

Answer:

$y+13=5(x+2)$

Step-by-step explanation:

The correct question is

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope form of the equation for this line?

we have

$y=5x-3$

This is the equation of the line in slope intercept form

where

the slope is $m=5$

the y-intercept is $b=-3$

Remember that

The equation of the line in point-slope form is equal to

$y-y1=m(x-x1)$

we have

$m=5$

$point\ (-2,-13)$

substitute

$y-(-13)=5(x-(-2))$

$y+13=5(x+2)$

3 0

3 years ago

Please help me asap!!!!!

Airida [17]

Answer:

y=0.5x+3

Step-by-step explanation:

7 0

3 years ago

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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?

d1i1m1o1n [39]

Given equation of the Circle is ,

$\sf\implies x^2 + y^2 = 25$

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

$\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2$

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

$\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }$

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

4 0

2 years ago

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