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Oduvanchick [21]
3 years ago
12

What digits can you insert so that 4 6 rounds to 500

Mathematics
1 answer:
Annette [7]3 years ago
3 0
You can round 46 to 50, not 500
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What value of x makes the equation below true 6x-7=26
VikaD [51]

Answer:

11/2

Step-by-step explanation:

6x−7=26

Step 1: Add 7 to both sides.

6x−7+7=26+7

6x=33

Step 2: Divide both sides by 6.

x= 11/2

6 0
3 years ago
Read 2 more answers
Describe the transformation from y= x + 4 to y= .5x + 4 Group of answer choices compresses stretches shifts right 4 shifts left
Nina [5.8K]

Answer:

This type of transformation is a horizontal stretch.

<em></em>

Step-by-step explanation:

Given

y = x + 4

y = .5x + 4

Required

Determine the type of transformation

The first function can be expressed as:

f(x) = x + 4

While the second function is:

g(x) = f(0.5x)

Solving f(0.5x), we have to substitute 0.5x for x in f(x) = x + 4

f(0.5x) = 0.5x + 4

So:

The second function is:

g(x) = 0.5x + 4

<em>This type of transformation is a horizontal stretch.</em>

<em></em>

<em>i.e. f(x) stretched to g(x)</em>

4 0
3 years ago
The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 54 -3. What is the point slope
dangina [55]

Answer:

y+13=5(x+2)

Step-by-step explanation:

<u><em>The correct question is</em></u>

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x -3. What is the point slope  form of the equation for this line?

we have

y=5x-3

This is the equation of the line in slope intercept form

where

the slope is m=5

the y-intercept is b=-3

Remember that

The equation of the line in point-slope form is equal to

y-y1=m(x-x1)

we have

m=5

point\ (-2,-13)

substitute

y-(-13)=5(x-(-2))

y+13=5(x+2)

3 0
3 years ago
Please help me asap!!!!!
Airida [17]

Answer:

y=0.5x+3

Step-by-step explanation:

7 0
3 years ago
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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
d1i1m1o1n [39]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

4 0
2 years ago
Read 2 more answers
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