3 years ago

What digits can you insert so that 4 6 rounds to 500

Mathematics

1 answer:

Annette [7]3 years ago

3 0

You can round 46 to 50, not 500

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3^x+2=8^x-1 Solve for x.

zubka84 [21]

I assume the equation is supposed to be

$3^{x+2}=8^{x-1}$

Then we can write

$9\cdot3^x=\dfrac18\cdot8^x\implies\left(\dfrac38\right)^x=\dfrac1{72}$

Take the logarithm of base 3/8 on both sides:

$\log_{3/8}\left(\dfrac38\right)^x=\log_{3/8}\dfrac1{72}$

$\implies x\log_{3/8}\dfrac38=-\log_{3/8}72$

$\implies x=-\log_{3/8}72$

- - -

If the equation is actually $3^x+2=8^x-1$ , I'm afraid it cannot be solved exactly.

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3 years ago