Answer:
2 7/12
Step-by-step explanation:
−512−−93=?
Since the the second fraction is negative and you are subtracting, remove the negative sign and switch the operation to addition.
The equivalent equation is
−512+93=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(-5/12, 9/3) = 12
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(−5/12×1/1)+(9/3×4/4)=?
Complete the multiplication and the equation becomes
−5/12+36/12=?
The two fractions now have like denominators so you can subtract the numerators.
Then:
−5+36/12=31/12
This fraction cannot be reduced.
The fraction
31/12
is the same as
31÷12
Convert to a mixed number using
long division for 31 ÷ 12 = 2R7, so
31/12=2 7/12
Therefore:
−5/12−−9/3=2 7/12
Answer:
solution given:
4(2x − 5) = 4
2x-5=4/4
2x=1+5
x=6
Step-by-step explanation:
Part A:One
Part B:x=6
A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.
B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127
We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y
In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5
x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5
So the cost of each student is $3.5, and the cost of each teacher is $5.
Hope this helps! :)
Answer:
It's a perfect cube, but not a perfect square.
Step-by-step explanation:
2^3 = 8, meaning 8 is a perfect cube. But since 2^2 = 4 and 3^2 = 9, and 8 is in between, 8 is not a perfect square.
I hope this helped.
Answer:The Answer is -23
Step-by-step explanation: