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Eduardwww [97]
3 years ago
12

Find the sum and product of the roots of each equation of

"x^{2}" alt="x^{2}" align="absmiddle" class="latex-formula"> - 16 =0
Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

\huge\boxed{\sf S = 0, P = -16}

Step-by-step explanation:

<u>Given the equation:</u>

\sf x^2 -16 = 0

Comparing it with \sf x^2-Sx+P= 0, where S is the sum and P is the product.

So,

Sum = S = 0

Product = P = -16

Hope this helped!

<h2>~AnonymousHelper1807</h2>

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3 years ago
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Alex73 [517]

y = - \frac{1}{4} x + \frac{15}{2}

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = 4x + 5 is in this form with slope m - 4

Given the slope of a line m, then the slope (m_{2}) of a line perpendicular to it is

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y = - \frac{1}{4} x + c is the partial equation of the perpendicular line

to find c, substitute ( 2, 7 ) into the partial equation

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3 years ago
Can someone help me on this ;-;
goldfiish [28.3K]

Answer:

4m+4

4(m+1)

Step-by-step explanation:

2m+m+m +2+2

Combine like terms

4m+4

Factor out 4

4(m+1)

6 0
3 years ago
Read 2 more answers
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