4 years ago

Please help!! I really need it thank you so much again!!

1 answer:

5 0

Here you go..............

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xxTIMURxx [149]

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Nostrana [21]

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4 years ago

blagie [28]

Answer:

The first and third quartile of the wingspans are 116.9 cm and 133.1 cm respectively.

Step-by-step explanation:

The first and third quartile of a normal distribution are:

$Q_{1}=\mu-0.675\sigma\\\\Q_{3}=\mu+0.675\sigma$

The information provided is as follows:

$\mu=125\\\sigma=12$

Compute the first and third quartile of the wingspans as follows:

$Q_{1}=\mu-0.675\sigma=125-(0.675\times 12)=116.9\\\\Q_{3}=\mu+0.675\sigma=125+(0.675\times 12)=133.1$

Thus, the first and third quartile of the wingspans are 116.9 cm and 133.1 cm respectively.

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3 years ago

svp [43]

Step-by-step explanation:

Median means the middle number

number already order

Median is 4 as there are 3 numbers to left and right

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3 years ago

marta [7]

The range is the y-values. Here is the answer and explanation :)

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3 years ago