__________ is the order of arrangement of files and folders.

Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth

telo118 [61]

Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}

So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.

4 0

3 years ago

Write a program and flowchart. The program should ask the user for the average temperature in each of the last 12 months. After

Afina-wow [57]

#First we define the variables to house the temperatures

#temp is an empty array that will be used to store the temperature

Temp = []

#The months is defined as stated below

months = 12

#Ask the user for the temperature input and unit if possible

print("Kindly enter the temperature here")

#the program enter loop to get the temperatures.

for x in range(months):

InitTemp = str(input("Kindly add the unit behind the number .eg C for celcius"))

Temp.append(InitTemp)

j=0

for x in range(len(Temp)):

j=j+1

print("The Temperature is", " ", Temp[x], "for the ", j, "Month" )

#there is an attached photo for the flowchart

5 0

3 years ago

The National Institute of Standards and Technology (NIST) guidelines list four different states a mobile device can be in when y

Ahat [919]

Answer:

quiescent

Explanation:

The National Institute of Standards and Technology (NIST) guidelines list four different states a mobile device can be in when you extract data. The quiescent mode is a dormant mode that conserves battery life while maintaining user data and performing other background functions.

4 0

3 years ago

Ethernet ensures that _____ on a shared network never interfere with each other and become unreadable.

Dmitry [639]

Answer:

Signals.

Explanation:

Encryption is a form of cryptography and typically involves the process of converting or encoding informations in plaintext into a code, known as a ciphertext. Once, an information or data has been encrypted it can only be accessed and deciphered by an authorized user.

Some examples of encryption algorithms are 3DES, AES, RC4, RC5, and RSA.

Ethernet ensures that signals on a shared network never interfere with each other and become unreadable through the use of encapsulation and standard encryption protocols.

In Computer Networking, encapsulation can be defined as the process of adding a header to a data unit received by a lower layer protocol from a higher layer protocol during data transmission. This ultimately implies that, the header (segment) of a higher layer protocol such as an application layer, is the data of a lower layer such as a transportation layer in the Transmission Control Protocol and Internet Protocol (TCP/IP).

The TCP/IP model comprises of four (4) layers;

1. Application layer: this is the fourth layer of the TCP/IP model. Here, the data unit is encapsulated into segments and sent to the transport layer.

2. Transport layer (layer 3): it receives the segment and encapsulates it into packets and sends to the internet layer.

3. Internet layer (layer 2): packets are encapsulated into frames.

4. Network layer (layer 1): frames are then converted into bits and sent across the network (LAN).

Hence, the data unit encapsulated inside a packet is known as segment, which is typically referred to as packet segmentation.

Additionally, these data, segments, packets, frames and bits transmitted across various layers are known as protocol data units (PDUs).

8 0

2 years ago

What are some of the strategies that you use for confronting a complex problem and breaking it down into smaller pieces? How mig

bazaltina [42]

Answer:

Breaking it down I guess for me, you could take down all the possible things that you could do. Eliminating things, one by one. It could help working on a computer by not letting yourself get over-whelmed by all your programming and thinking "alright, this THEN this."

Explanation:

8 0

3 years ago