A=(psr^2)/360
360A=psr^2
s=(360A)/(pr^2)
The maximum of this parabola is (3/4,16).
Therefore since time is on the x-axis, the ball reaches the maximum height at 3/4secs.
And since the height is on the y-axis, the ball will each a maximum height of 16ft.
By common multiple method and division method
The dimensions if the field are: the length is 360 feet; the width is 160 feet.
